Question

我想查找特定商品的未偿还总额（退款金额除外）。

根据商品的销售次数，每个商品都会有两列，分别是final_amount和第二个refund_amount，我想从{{1 }}。

PFB代码/查询

refund_amount

我在

附近收到“ SUM”的语法错误

final_amount

我尝试了不同的代码：

SELECT item_id,
       SUM(final_amount) as total_amount,
       SUM(ISNULL(refund_amount, 0)) AS total_refund
       SUM(final_amount) - SUM(ISNULL(refund_amount, 0)) AS outstanding_amount                    
FROM tabel1 
WHERE item_id in ('119688521',
                  '109536343',
                  '99459466',
                  '97126817',
                  '138148320',
                  '107816131')
GROUP BY 1

我也遇到同样的错误。

Answer 1

首先，语法上有一些错误。您在所有选择元素之间（在total_refund和outstanding_amount之间）都缺少逗号。您还应该检查SUM()是否为空，而不是列是否为空。如果愿意，也可以使用COALESCE()。最后，您需要GROUP BY，例如item_id。

SELECT item_id,
       SUM(final_amount) as total_amount,
       ISNULL(SUM(refund_amount), 0) AS total_refund,
       SUM(final_amount) - ISNULL(SUM(refund_amount), 0) AS outstanding_amount
FROM tabel1 WHERE item_id in ('119688521',
                              '109536343',
                              '99459466',
                              '97126817',
                              '138148320',
                               '107816131')

GROUP BY item_id

http://www.sqlfiddle.com/#!18/94f518/5上的实时演示

Answer 2

您缺少逗号。此外，您应该在NULL之后检查SUM() ：

SELECT item_id, SUM(final_amount) as total_amount, COALESCE(SUM(refund_amount), 0) AS total_refund, (SUM(final_amount) - COALESCE(SUM(refund_amount), 0) ) AS outstanding_amount FROM tabel1 WHERE item_id in ('119688521', '109536343', '99459466', '97126817', '138148320', '107816131') GROUP BY 1

Answer 3

尝试一下

SELECT item_id,
SUM(final_amount) as total_amount,
SUM(ISNULL(refund_amount, 0)) AS total_refund

SUM(final_amount - isnull(refund_amount, 0)) AS outstanding_amount

FROM tabel1 WHERE item_id in ('119688521',
'109536343',
'99459466',
'97126817',
'138148320',
'107816131')

GROUP BY item_id

Answer 4

您不希望在“ .... AS total_refund”列后面加上逗号（，）。添加逗号，这将解决语法问题。

请使用GROUP BY item_id代替GROUP BY 1

如何在SQL查询中减去2 SUM

4 个答案: