Question

我是 Python 新手，我正在尝试询问用户是否想再次使用我的年龄计算器工具。代码：

while True:
    import datetime
    birth_year = int(input("What year were you born? "))
    current_year = datetime.datetime.now().year
    age = current_year - birth_year
    print(f"You are {age} years old now.")
    input()
    choice = input("Do you want to go again? (yes or no) ")
if "choice" == yes:
    print("enjoy")
elif "choice" == no:
    print ("Ok, quitting now")
    quit()
else:
    print("i'll assume that means yes")

Answer 1

import datetime
while True:
    birth_year = int(input("What year were you born? "))
    current_year = datetime.datetime.now().year
    age = current_year - birth_year
    print(f"You are {age} years old now.")
    choice = input("Do you want to go again? (yes or no) ")
    if choice == 'yes':
        print("enjoy")
    elif choice == 'no':
        print ("Ok, quitting now")
        break
    else:
        print("i'll assume that means yes")

您可以将所有内容无限循环并在用户输入“否”时中断它。

Answer 2

您的错误是您调用变量 choice 并用引号将其括起来，使其成为字符串 "choice"。相反，您应该检查变量 choice 是否包含字符串“yes”或“no”。
为此，我们可以使用两个运算符，== 或 is 运算符。
下面是一个例子：

import datetime
birth_year = int(input("What year were you born? "))
current_year = datetime.datetime.now().year
age = current_year - birth_year
print(f"You are {age} years old now.")
input()
choice = input("Do you want to go again? (yes or no) ")
if choice == 'yes': # Example using the `==` operator.
    print("enjoy")
elif choice is 'no': # Example using the `is` operator.
    print ("Ok, quitting now")
    exit() # This should be `exit` not `quit`.
else:
    print("i'll assume that means yes")

如何让此代码识别我的输入？

2 个答案: