如何在不同的类中访问NSURLResponse

时间:2011-07-13 21:51:38

标签: iphone objective-c nsurlconnection nsurl nsurlrequest

我有以下zipfile类,它执行我的zip文件的下载。我有一个与我的zip文件关联的文件名。我需要知道要传递给viewcontroller类的文件名。每当我尝试从不同的类访问值时,它总是返回null。我实际上想知道如何使用ZipFile中的responseString并在ViewController中使用它。

/ ZipFile.m /

-(NSString *) downloadZipFile{


fileManager = [NSFileManager defaultManager];

NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
directoryPath = [paths objectAtIndex:0];
filePath = [NSString stringWithFormat:@"%@/ZipFiles.zip", directoryPath];

NSURL *url=[NSURL URLWithString:@"http://www.abc.com/id=123"];

NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease];
[request setURL:url];
[request setHTTPMethod:@"POST"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];

NSError *error1;
urlData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error1];

[fileManager createFileAtPath:filePath contents:urlData attributes:nil];

[SSZipArchive unzipFileAtPath:filePath toDestination:directoryPath];
NSLog(@"Finished unzipping database");

Tab_Table_WinAppDelegate *appDelegate = [[[Tab_Table_WinAppDelegate alloc] init] autorelease];
[appDelegate loadingViewControllerDidFinish];

NSString *total = [self total]; // returns value here
return total;
}


- (NSString *)total {


NSString *responseString = [[NSString alloc] initWithData:urlData encoding:NSASCIIStringEncoding];
NSString *fileName = [response suggestedFilename];
NSLog(@"Value : %@", fileName);

return fileName;
   }

/ * ViewController.m * /

- (CGSize)imageSizeAtIndex:(NSUInteger)index {
CGSize size = CGSizeZero;
if (index < [self imageCount]) {

    ZipFile *map = [[ZipFile alloc]init];
    size.width = [[map total] floatValue]; // returns null here

    [map release];
}
return size;
 }

1 个答案:

答案 0 :(得分:0)

    ZipFile *map = [[ZipFile alloc]init];

这会创建一个新的ZipFile,这可能不是你想要做的。你需要一些方法将你真正感兴趣的ZipFile对象传递给控制器​​。