我有一个简单的NSURLRequest:
[NSURLConnection sendAsynchronousRequest:myRequest queue:queue completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {
// do stuff with response if status is 200
}];
如何获取状态代码以确保请求正常?
答案 0 :(得分:193)
从响应中投射NSHTTPURLResponse
的实例并使用其statusCode
方法。
[NSURLConnection sendAsynchronousRequest:myRequest queue:queue completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {
NSHTTPURLResponse *httpResponse = (NSHTTPURLResponse *) response;
NSLog(@"response status code: %ld", (long)[httpResponse statusCode]);
// do stuff
}];
答案 1 :(得分:26)
在使用iOS 9的Swift中,您可以这样做:
if let url = NSURL(string: requestUrl) {
let request = NSMutableURLRequest(URL: url, cachePolicy: NSURLRequestCachePolicy.ReloadIgnoringLocalAndRemoteCacheData, timeoutInterval: 300)
let config = NSURLSessionConfiguration.defaultSessionConfiguration()
let session = NSURLSession(configuration: config)
let task = session.dataTaskWithRequest(request, completionHandler: { (data, response, error) -> Void in
if let httpResponse = response as? NSHTTPURLResponse {
print("Status code: (\(httpResponse.statusCode))")
// do stuff.
}
})
task.resume()
}
答案 2 :(得分:3)
Swift 4
let task = session.dataTask(with: request, completionHandler: { data, response, error -> Void in
if let httpResponse = response as? HTTPURLResponse {
print("Status Code: \(httpResponse.statusCode)")
}
})
task.resume()