一个端点中的多个功能 fastapi

时间:2021-03-27 08:07:39

标签: python fastapi

我正在尝试创建一个音频服务器,我可以在其中上传各种音频文件,我有一个要求,我只能创建一个用于创建的端点,我想出了这个,但它确实显示了输入数据的请求表单。

class AudioType(str, Enum):
    Song = "Song"
    Podcast = "Podcast"
    Audiobook = "Audiobook"


@app.post("/{audio_type}", status_code=status.HTTP_200_OK)
def audio(audio_type: AudioType):
    if audio_type == AudioType.Song:
        def create_song(request: schemas.Song, db: Session = Depends(database.get_db)):
            new_song = models.Song(name=request.name, duration=request.duration, uploadTime=request.uploadTime)
            db.add(new_song)
            db.commit()
            db.refresh(new_song)
            return new_song
    elif audio_type == AudioType.Podcast:
        def create_podcast(request: schemas.Podcast, db: Session = Depends(database.get_db)):
            new_podcast = models.Podcast(name=request.name,  duration=request.duration, uploadTime=request.uploadTime,                                         host=request.host)
            db.add(new_podcast)
            db.commit()
            db.refresh(new_podcast)
            return new_podcast
    elif audio_type == AudioType.Audiobook:
        def create_audiobook(request: schemas.Audiobook, db: Session = Depends(database.get_db)):
            new_audiobook = models.Audiobook(titile=request.title, author=request.author, narrator=request.narrator,                                              duration=request.duration, uploadTime=request.uploadTime)
            db.add(new_audiobook)
            db.commit()
            db.refresh(new_audiobook)
            return new_audiobook

1 个答案:

答案 0 :(得分:1)

您的方法不接受 request 对象,而只接受 audio_type
此外,根据我从您的代码中了解到的情况,您可能有多个请求正文(schemas,如您所指)

您有两种选择:

  1. 您需要按如下方式声明端点:

    from typing import Union
    
    @app.post("/{audio_type}", status_code=status.HTTP_200_OK)
    def audio(
        request: Union[schemas.Song, schemas.Podcast, 
        schemas.Audiobook], audio_type: AudioType
    ):
        ... Your method ...
    

    但是 fastapi 的 auto swagger 不会提供模式示例,您必须手动提供示例,(这可能也可能不可能,我真的不知道也没有尝试过:/)

  2. 或者您可以拥有一个可以接受所有内容作为 Optionalaudio_type 参数的架构:

    from typing import Optional
    
    
    class EndpointSchema(BaseModel):
        audio_type: AudioType
        song: Optional[schemas.Song]
        podcast: Optional[schemas.Podcast]
        audiobook: Optional[schemas.Audiobook]
    
    
    @app.post("/audio", status_code=status.HTTP_200_OK)
    def audio(request_body: EndpointSchema):
        if request_body.audio_type == AudioType.Song:
            ... Continue with your request processing ...
    

最后,非常重要:您声明了之后不会调用的内部方法(create_song 等),因此您的代码将不执行任何操作。您不需要这样做,直接在 if, elif ... 块内使用您想要创建歌曲、播客或有声读物的代码!