Question

我不知道我是否在监督它或什么，但我不知道如何获得 else if 语句的结果，例如，我有这段代码，我一直在练习：

在这种情况下，结果将是“它很温暖！”，我想做的是创建一个取决于结果的代码，但结果它不是一个变量，那么我如何创建一个代码响应记录的内容？例如，如果它记录：“天气很暖和！”我想添加诸如“打开空调”之类的内容。或“打开加热器”或其他。我该怎么做？

let temperature = 36
if (temperature > 24) {
console.log ("It's warm!");
} else if (temperature < 24) {
    console.log ("It's cold!");    
} else {
    console.log ("It's cool!");

Answer 1

您可以将其保存为变量：

let temperature = 36;
const isCold = temperature < 24;
const isWarm = temperature > 24;
if (isWarm) {
    console.log("It's warm!");
} else if (isCold) {
    console.log("It's cold!");
} else {
    console.log("It's cool!");
}

if (isWarm) {
    console.log("Turn on the A/C!");
}

Answer 2

您可以在 if 条件后用 {} 定义的表达式块中设置代码..

例如：

let temperature = 36;
if (temperature > 24) {
  console.log("It's warm!");
  console.log("Turn on the AC.");
  // You can write coode base in this condition as much you want
  // or you can call another function
} else if (temperature < 24) {
  console.log("It's cold!");
} else {
  console.log("It's cool!");
}

Answer 3

不太清楚你的意思，但如果你想输出温度：

let temperature = 36
if (temperature > 24) {
console.log ("It's warm!", temperature, "degrees");
} else if (temperature < 24) {
    console.log ("It's cold!", temperature, "degrees");    
} else {
    console.log ("It's cool!", temperature, "degrees);

Answer 4

将结果放入变量中。

let temperature = 36;
let result = '';
if (temperature > 24) {
  result = "It's warm!";
} else if (temperature < 24) {
  result = "It's cold!";
} else {
  result = "It's cool!";
}

console.log (result);

Answer 5

您可以在函数中设置一个变量 - 将温度传递给函数并输出结果 - 请注意 switch statement 的使用，它将输入的温度与条件进行比较并更新结果字符串。这就是 switch 语句的用途 - 提供嵌套或复杂 if else 语句的替代方案。

function setTemperature(temp){
 let result = "It's ";
  switch (true) {
    case temp > 24:
    result += "warm!";
    break;
    
    case temp > 12:
    result += "cool!";
    break;
    
    default:
    result += "cold!";
  }
  return result;
}

    
console.log( setTemperature(36)); // gives "It's warm!"
console.log( setTemperature(16)); // It's cool!
console.log( setTemperature(6)); //It's cold!

Answer 6

你可以像这样创建一个函数：

let temperature = 36;
function myFunct(temp){ // "myFunct" can be anything
    if (temp > 24) {
        return "It's warm!";
    } else if (temp < 24) {
        return "It's cold!";    
    } else {
        return "It's cool!";
    }
}

var t = myFunct(temperature); // get whether it's warm, cold, or cool

console.log(t); // tell the user if it's warm, cold, or cool

// do something!
if(t === "It's warm!"){
    // run something here if it's warm
} else if (t === "It's cold!"){
    // run something here if it's cold
} else {
    // run something here if it's cool
}

虽然你可以在函数或原始 if 语句中运行一些东西。

希望这有帮助！

如何获取If/If else语句的结果

6 个答案: