如何根据另一个数组过滤一个数组中的数据

Question

假设我有 2 个数组 arr1=["a","b","c","d","e"] 基于arr2 = [1,3] 所需的输出为 arr1 = ["b","d"]

Answer 1

valueArray = ["a","b","c","d","e"]; // arr1
indexArray = [1,3]; // arr2

valueArray = indexArray.map(index => valueArray[index]);

console.log(valueArray);

Answer 2

只需执行以下顺序：

const arr1=["a","b","c","d","e"];
const arr2 = [1,3];
const filteredArray = arr1.filter((_,index)=>{
 return arr2.includes(index)
});
console.log(filteredArray)

Answer 3

我假设您想要第一个数组的值以及第二个数组中提供的索引。您可以通过以下方法实现这一点

arr2.forEach(value => d.push(arr1[value]))

Answer 4

您可以使用地图：

[PC]\(\d+[ ,]\s*\d+\)