Question

我有一个数组VIPArray和AddressArray，因此我想根据AddressArray过滤VIPArray。我怎么能这样做？

VIPArray看起来像这样

let VIPArray = [["name": "John B"], ["name": "Sara K"]]

AddressArray看起来像这样

let AddressArray = [Address(name: "John B",  imageURL: "johnb", address: "178 Main St."),
                    Address(name: "Dave H",  imageURL: "daveh", address: "1011 Victoria St.."),
                    Address(name: "Sara K",  imageURL: "sarak", address: "279 Maple Av."),
                    Address(name: "Niles K", imageURL: "nilesk", address: "45 King St."),
                    Address(name: "Ingrid G",  imageURL: "ingridg", address: "33 Union St.")

所以我想得到这个结果:(过滤的AddressArray）

[
    Address(name: "John B",  imageURL: "johnb", address: "178 Main St."),
    Address(name: "Sara K",  imageURL: "sarak", address: "279 Maple Av.")
]

Answer 1

1。您只需使用for-in loop和filter即可获得预期值：

    for VIP in VIPArray
    {
        let result = AddressArray.filter({ $0.name == VIP["name"] })
        print(result)
    }

2. 或者，您可以使用map和filter的组合来获取预期值。

    let result = VIPArray.map { (VIP) -> Address? in
        if let address = AddressArray.filter({ $0.name == VIP["name"] }).first
        {
                return address
        }
        return nil
    }
    print(result)

如果您仍然遇到任何问题，请告诉我。

Answer 2

struct Address {
    var name: String
    var imageURL: String
    var address: String
}

let VIPArray = [["name": "John B"], ["name": "Sara K"]]

let AddressArray = [Address(name: "John B",  imageURL: "johnb", address: "178 Main St."),
                    Address(name: "Dave H",  imageURL: "daveh", address: "1011 Victoria St.."),
                    Address(name: "Sara K",  imageURL: "sarak", address: "279 Maple Av."),
                    Address(name: "Niles K", imageURL: "nilesk", address: "45 King St."),
                    Address(name: "Ingrid G",  imageURL: "ingridg", address: "33 Union St.")]


var filtered = [Address]()

for element in VIPArray {
    for address in AddressArray {
        if element["name"] == address.name {
            filtered.append(address)
        }
    }
}

for record in filtered {
    print(record)
}

输出：

地址（姓名：“John B”，imageURL：“johnb”，地址：“178 Main St。”）

地址（姓名：“Sara K”，imageURL：“sarak”，地址：“279 Maple Av。”）

或者：

let filtered: [Address] = AddressArray.filter { (address) -> Bool in
    for vip in VIPArray {
        if vip["name"] == address.name {
            return true
        }
    }
    return false
}

Answer 3

let VIPArray = [["name": "John B"], ["name": "Sara K"]]

struct Address {
    let name: String
    let imageURL: String
    let address: String
}

let addressArray = [Address(name: "John B",  imageURL: "johnb", address: "178 Main St."),
                    Address(name: "Dave H",  imageURL: "daveh", address: "1011 Victoria St.."),
                    Address(name: "Sara K",  imageURL: "sarak", address: "279 Maple Av."),
                    Address(name: "Niles K", imageURL: "nilesk", address: "45 King St."),
                    Address(name: "Ingrid G",  imageURL: "ingridg", address: "33 Union St.")]

let myVips = addressArray.filter() {VIPArray.contains(["name":$0.name])}

Swift如何根据另一个数组过滤数组

3 个答案: