Question

membership表

membership_startdate
member_dueday

要查看成员从membership_startdate到目前为止支付的款项（月数），并考虑到：

SELECT DATEDIFF(GREATEST(NOW(), memberToMship_DueDay), memberToMship_StartDate) AS diff 
  FROM membertomship

...但是当我们认为memberToMship_StartDate是2011-07-01并且mmebership_dueday是07时结果是06，但是错误的结果是错误的结果。

如果memberToMship_StartDate为“2011-01-01”且截止日期为15，那么结果将近6个月（jan - jun）（根据月份的第15个月）。

我正在使用mysql

我试过这个

                      SELECT DATE_SUB(DATE_ADD(memberToMship_StartDate,GREATEST(NOW(), memberToMship_DueDay)), INTERVAL memberToMship_DueDay DAY ) AS diff FROM membertomships;

但它给出了错误，如

                 Error Code: 1064
                         You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'GREATEST(NOW(), memberToMship_DueDay)), INTERVAL memberToMship_DueDay DAYS ) AS ' at line 1

Answer 1

好的，这是解决方案：

SELECT
    PERIOD_DIFF(DATE_FORMAT(now(),'%Y%m'), DATE_FORMAT(membership_StartDate,'%Y%m')) -- month difference
    + (DAY(membership_StartDate) < member_dueday) -- +1 if the start date was before the due day
    + (DAY(now()) > member_dueday) -- +1 if "now" is after the due day
    - 1 -- needed due to the way we are calculating our own adjustments for due day
    as payment_count
from membertomships;

以下是一些显示边缘情况的测试数据：

create table membertomships (id int auto_increment primary key, membership_startdate date, member_dueday int);
insert into membertomships values (null, '2011-05-01', 15);
insert into membertomships values (null, '2011-05-30', 15);
insert into membertomships values (null, '2011-05-01', 4);
insert into membertomships values (null, '2011-05-30', 4);
SELECT
    membership_StartDate as start,
    member_dueday as due,
    current_date as today,
    PERIOD_DIFF(DATE_FORMAT(now(),'%Y%m'), DATE_FORMAT(membership_StartDate,'%Y%m')) - 1 + (DAY(membership_StartDate) < member_dueday) + (DAY(now()) > member_dueday) as payment_count
from membertomships;
SELECT id, membership_StartDate as start_date, member_dueday as due_day, current_date as today,
PERIOD_DIFF(DATE_FORMAT(now(),'%Y%m'), DATE_FORMAT(membership_StartDate,'%Y%m')) - 1 + (DAY(membership_StartDate) < member_dueday) + (DAY(now()) > member_dueday) as payment_count
from membertomships;
+----+------------+---------+------------+---------------+
| id | start_date | due_day | today      | payment_count |
+----+------------+---------+------------+---------------+
|  1 | 2011-05-01 |      15 | 2011-07-08 |             2 |
|  2 | 2011-05-30 |      15 | 2011-07-08 |             1 |
|  3 | 2011-05-01 |       4 | 2011-07-08 |             3 |
|  4 | 2011-05-30 |       4 | 2011-07-08 |             2 |
+----+------------+---------+------------+---------------+

给出错误结果的月数

1 个答案: