Question

我修改了PHP中的函数以返回颜色渐变（http://www.herethere.net/~samson/php/color_gradient/color_gradient_generator.php.txt）。返回以0结尾的颜色十六进制代码时出现问题。这是功能：

def _get_color(current_step=0, start='000000', end='ffffff', max_steps=16):
    '''
        Returns the color code for current_step between start and end
    '''
    start = '{0:#x}'.format(int(start, 16))
    end = '{0:#x}'.format(int(end, 16))

    if int(max_steps) > 0 & int(max_steps) < 256:
        max_steps = max_steps
    else:
       max_steps = 16

    r0 = (int(start, 16) & 0xff0000) >> 16
    g0 = (int(start, 16) & 0x00ff00) >> 8
    b0 = (int(start, 16) & 0x0000ff) >> 0

    r1 = (int(end, 16) & 0xff0000) >> 16
    g1 = (int(end, 16) & 0x00ff00) >> 8
    b1 = (int(end, 16) & 0x0000ff) >> 0

    if r0 < r1:
        r = int(((r1-r0)*(float(current_step)/float(max_steps)))+r0)
    else:
        r = int(((r0-r1)*(1-(float(current_step)/float(max_steps))))+r1)

    if g0 < g1:
        g = int(((g1-g0)*(float(current_step)/float(max_steps)))+g0)
    else:
        g = int(((g0-g1)*(1-(float(current_step)/float(max_steps))))+g1)

    if b0 < b1:
        b = int(((b1-b0)*(float(current_step)/float(max_steps)))+b0)
    else:
        b = int(((b0-b1)*(1-(float(current_step)/float(max_steps))))+b1)

    return '{0:#x}'.format(((((r << 8) | g) << 8) | b))

当我运行一个盯着＃000000黑色的循环时，我只返回0.第二个代码f0f0f也缺少一个0。

for i in range(0, 16):
    print _get_color(current_step=i, start='000000', end='ffffff', max_steps=16)

0
f0f0f
1f1f1f
2f2f2f
3f3f3f
4f4f4f
5f5f5f
6f6f6f
7f7f7f
8f8f8f
9f9f9f
afafaf
bfbfbf
cfcfcf
dfdfdf
efefef

注意前两个十六进制代码。关于如何正确格式化返回值以返回000000的任何想法？

Answer 1

>>> print '{0:06x}'.format(123)
00007b

Python中十六进制颜色的字符串格式

1 个答案: