我有一个调用其他视图[xib]的视图[xib], 当我转到第二个视图时,一个值被发送到第二个视图.m
initWithNibName
但是当我将第二个视图称为模态视图时,我的消息不会被发送,
我该怎么办?
Contacts *info = [XlistArray objectAtIndex:indexPath.row];
string1 = info.c_name;
editContactViewController *mensaje =[editContactViewController alloc];
mensaje.string2 = string1;
editContactViewController *vistaEdit = [[editContactViewController alloc] initWithNibName:nil bundle:nil];
vistaEdit.modalPresentationStyle = UIModalPresentationFormSheet;
[self presentModalViewController:vistaEdit animated:YES];
/*
Contacts *info = [XlistArray objectAtIndex:indexPath.row];
string1 = info.c_name;
editContactViewController *mensaje =[editContactViewController alloc];
mensaje.string2 = string1;
editContact = [[editContactViewController alloc] initWithNibName:@"editContactViewController" bundle:nil];
[self.view addSubview:mensaje.view];
[UIView commitAnimations];
[tableView deselectRowAtIndexPath:indexPath animated:YES];*/
请注意string1是我的发件人邮件,string2是我的收件人, 评论部分是用于发送的部分,
我该如何发送消息?基本抱歉
非常感谢!
答案 0 :(得分:1)
tnx到dany_dev
Contacts *info = [XlistArray objectAtIndex:indexPath.row];
string1 = info.c_name;
editContactViewController *vistaEdit = [[editContactViewController alloc] initWithNibName:nil bundle:nil];
vistaEdit.string2 = string1;
vistaEdit.modalPresentationStyle = UIModalPresentationFormSheet;
[self presentModalViewController:vistaEdit animated:YES];