是否有一个宝石或其他东西来解析像“4h 30m”“1d 4h”这样的字符串 - 有点像JIRA或任务规划人员的估计,也许是国际化?
答案 0 :(得分:12)
发布第二个答案,因为慢性(我的原始答案建议)不会给你时间戳而是时间戳。
这是我的解析器。
class TimeParser
TOKENS = {
"m" => (60),
"h" => (60 * 60),
"d" => (60 * 60 * 24)
}
attr_reader :time
def initialize(input)
@input = input
@time = 0
parse
end
def parse
@input.scan(/(\d+)(\w)/).each do |amount, measure|
@time += amount.to_i * TOKENS[measure]
end
end
end
策略相当简单。将"5h"
拆分为["5", "h"]
,定义"h"
代表的秒数(TOKENS
),并将该金额添加到@time
。
TimeParser.new("1m").time
# => 60
TimeParser.new("1m wtf lol").time
# => 60
TimeParser.new("4h 30m").time
# => 16200
TimeParser.new("1d 4h").time
# => 100800
让它处理"1.5h"
也不会太难,因为看到代码库就像它一样简单。
答案 1 :(得分:9)
chronic_duration
这样做。
答案 2 :(得分:6)
您可以使用chronic。它几乎可以解析你所做的一切,包括“昨天”,“上周”等等。
更新:正如OP在评论中指出的那样,Chronic是针对日期而不是时间跨度。看到我的其他答案。
答案 3 :(得分:3)
我写的这个方法很好用
def parse_duration(dur)
duration = 0
number_tokens = dur.gsub(/[a-z]/i,"").split
times = dur.gsub(/[\.0-9]/,"").split
if number_tokens.size != times.size
raise "unrecognised duration!"
else
dur_tokens = number_tokens.zip(times)
for d in dur_tokens
number_part = d[0].to_f
time_part = d[1]
case time_part.downcase
when "h","hour","hours"
duration += number_part.hours
when "m","minute","minutes","min","mins"
duration += number_part.minutes
when "d","day","days"
duration += number_part.days
when "w","week","weeks"
duration += number_part.weeks
when "month", "months"
duration += number_part.months
when "y", "year", "years"
duration += number_part.years
else
raise "unrecognised duration!"
end
end
end
duration
end
答案 4 :(得分:1)
虽然解析了什么?
这将解析为Hash:
"4h 30m".split(/\s/).each{|i| h[i.gsub(/\d+/,"")] = i.gsub(/\w/,"")}
对不起。不熟悉JIRA ......