我有一个List对象,其中包含Id值,例如它包含: 1,2,10,1,23,11,1,4,2,2,...等我需要找出有多少次“1”,“2”,......等已经发生 在C#中使用Linq
请帮助。
答案 0 :(得分:13)
使用Enumerable.GroupBy
非常简单:
var grouped = list.GroupBy(x => x);
foreach (var group in grouped)
{
Console.WriteLine("{0} appears {1} times", group.Key, group.Count());
}
或者:
var query = list.GroupBy(x => x, (x, g) => new { Key = x, Count = g.Count() }));
foreach (var result in query)
{
Console.WriteLine("{0} appears {1} times", result.Key, result.Count);
}
(区别在于我们真正将组转换为结果。)
答案 1 :(得分:12)
使用GroupBy:
var les = new[] { 1, 2, 10, 1, 23, 11, 1, 4, 2, 2 };
var result = les
.GroupBy(i => i, (e, g) => new { Value = e, Count = g.Count() });
或使用替代语法:
var result =
from i in les
group i by i
into g
select new { Value = g.Key, Count = g.Count() };
答案 2 :(得分:3)
var l = new List<int> {1,2,10,1,23,11,1,4,2,2};
l.GroupBy(i => i)
.ToList()
.ForEach(g => Console.WriteLine("{0} : {1}", g.Key, g.Count()));
答案 3 :(得分:2)
var list = new List<int> { 1, 2, 10, 1, 23, 11, 1, 4, 2, 2, };
var groups = list.GroupBy(i => i);
foreach (var group in groups)
Console.WriteLine("{0} occurs {1} times", group.Key, group.Count());