Question

我刚刚开始使用Python并编写一个简单的石头剪刀游戏。 Here's到目前为止我所拥有的。我可以完美地与其他玩家玩游戏。我想知道的是如何保持胜利的得分，所以如果玩家1赢得第一场比赛就会说：

玩家1 = 1 玩家2 = 0

等等。此外，如果有任何提示可以使我的代码更有效（有一个很好的解释），那就太好了。

谢谢！

Answer 1

考虑这个伪代码的建议（某些部分需要实现）：

# a Player class. it should have a Name and a Score
class Player():
   def __init__(name):
      self.name = name
      self.score = 0

# displays a prompt and reads in the players name returning a string
def getPlayerName():
   # needs code here, see next function for idea of what
   pass

# ask the player to make a choice, takes a Player object
# and returns a string
def getPlayerAttack(player):
    print "%s, what do you choose?" % player.name
    return raw_input("> ")

# determines who wins and updates score accordingly
# takes in the player objects and their attack choices
def attack(player1, choice1, player2, choice2): 
    if choice1 == choice2:
       print "Its's a tie."
    elif choice1 == "1" and choice2 == "2":
       print "%s wins." % player2
       player2.score = player2.score + 1
    elif ... # other attacks

# display the scores of the two players
def displayScores(player1, player2):
    print "%s vs %s" % (player1.score, player2.score)

player1 = Player(getPlayerName())
player2 = Player(getPlayerName())
while true:
    choice1 = getPlayerAttack(player1)
    choice2 = getPlayerAttack(player2)
    attack(player1, choice1, player2, choice2)
    displayScores(player1, player2)

这需要一些工作，并且不超级优化，但它应该是一个开始，应该显示更多的概念。使用Ctrl-C停止或添加停止条件（例如，任一玩家输入“0”） - 免费包含错误。 :)

快乐的编码。

Answer 2

有几种方法可以提高它的效率，但如果你必须一次输入一个，我必须问你如何玩Rock Paper Scissors :-P

得分可以归结为：

if choice1 == choice2 :
    print "Its's a tie."
elif choice1 - choice2 == 1 or choice2 - choice1 == 2 :
    print "%s wins." % player1
else:
    print "%s wins." % player2

如果你想做多个游戏，只需将整个事情放在while(1):循环中，并为每个分数添加一个变量。然后它会变成：

score1 = 0
score2 = 0
while(1):
    <lines 6-18>

    if choice1 == choice2 :
        print "Its's a tie."
    elif choice1 - choice2 == 1 or choice2 - choice1 == 2 :
        print "%s wins." % player1
        score1 = score1 + 1
    else:
        print "%s wins." % player2
        score2 = score2 + 1

    print "%s: %d points. %s: %d points." % (player1, score1, player2, score2)

Answer 3

试试这个：

player1 = raw_input("Player 1 name: ")
player2 = raw_input("Player 2 name: ")
while(1)
    player1score = 0
    player2score = 0

    print "%s, what do you choose?" % player1
    print "1. Rock"
    print "2. Paper"
    print "3. Scissors"

    choice1 = raw_input("> ")

    print "%s, what do you choose?" % player2
    print "1. Rock"
    print "2. Paper"
    print "3. Scissors"

    choice2 = raw_input("> ")

    if choice1 == "1" and choice2 == "1":
        print "Its's a tie."

    if choice1 == "1" and choice2 == "2":
        print "%s wins." % player2
        player2score=player2score+1

    if choice1 == "2" and choice2 == "1":
        print "Player 1 wins." % player1
        player1score=player1score+1

    if choice1 == "1" and choice2 == "3":
        print "Player 1 wins." % player1
        player1score=player1score+1

    if choice1 == "3" and choice2 == "1":
        print "%s2 wins." % player2
        player2score=player2score+1

    if choice1 == "2" and choice2 == "3":
        print "%s wins." % player2
        player2score=player2score+1

    if choice1 == "3" and choice2 == "2":
        print "Player 1 wins." % player1
        player1score=player1score+1

    print "Player1: %s" % player1score 
    print "Player2: %s" % player2score

如何在石头剪刀游戏中保持得分？

3 个答案: