我有以下代码,它接受一个字符串数组,并将其拆分为2个字符串:
$key2 = $count = count($textArray);
$key = 0;
while ($key2 >= $count/2){
$this -> text1 = $this-> text1 . $textArray[$key];
$this -> text2 = $textArray[$key2] . $this-> text2;
$key++;
$key2--;
}
现在在5索引数组上我将它分成3-2,我想将它分成2-3,所以在text1上,我只会连接2个字符串,
这是非常简单的事情,但我无法做到。
答案 0 :(得分:0)
这个怎么样?
<?php
$arr = array("qwe","rty","asd","zxc","fgh","xxx","abvah");
$arrNew = array_chunk($arr,ceil(count($arr)/2.0));
$text1 = "";
$text2 = "";
/*foreach ($arrNew[0] as $arr1){
$text1 .= $arr1;
}
foreach ($arrNew[1] as $arr2){
$text2 .= $arr2;
}*/
array_map(function($x) use($text1){$text1 .= $x;},$arrNew[0]);
array_map(function($x) use($text2){$text2 .= $x;},$arrNew[1]);
print "$text1\n$text2\n";
?>
答案 1 :(得分:0)
我希望我能正确阅读你的问题:
$strings = array('a', 'b', 'c', 'd', 'f');
$new = array_map(function ($arr) {
return implode('', $arr);
}, array(array_splice($strings, 0, floor(sizeof($strings) / 2)), $strings));
print_r($new);
输出:
Array
(
[0] => ab
[1] => cdf
)