Question

我有一个包含两个数组的php对象，我需要一次遍历两个数组并显示select选项。 table->list应该位于值的内部，而tables->title应该位于选项HTML输出的内部。

这是我的代码：

$tables = new \stdClass();
$tables->list =  ['bmg_contact_us','bmg_volunteer'];
$tables->title = ['Contact us', 'Volunteer'];

<select name="bmg-forms" onchange="submission_frm.submit();">

<?php
foreach ($tables as $key => $table) {
 echo "<option value='" . $tables->list . "'>'" . $tables->title . "'</option>";    
}
?>
</select>

Answer 1

$tables = new \stdClass();
$tables->list =  ['bmg_contact_us','bmg_volunteer'];
$tables->title = ['Contact us', 'Volunteer'];
$options = array_combine($tables->list,$tables->title);//both array count must be same

输出：

Array
(
    [bmg_contact_us] => Contact us
    [bmg_volunteer] => Volunteer
)

html：

<select name="bmg-forms" onchange="submission_frm.submit();">

<?php
foreach ($options as $key => $value) {
 echo "<option value='" . $key . "'>'" . $value . "'</option>";    
}
?>
</select>

Answer 2

您需要循环内部数组，然后使用键获取标题。

foreach ($tables->list as $key => $table) {
 echo "<option value='" . $table . "'>'" . $tables->title[$key] . "'</option>";    
}

输出：

<option value='bmg_contact_us'>'Contact us'</option>
<option value='bmg_volunteer'>'Volunteer'</option>

https://3v4l.org/i1dcT

Answer 3

最简单的方法是创建一个关联的数组（from_raw）并对其进行迭代。

在您的示例中：

 $tables->options = [
    'bmg_contact_us' => 'Contact us', 
    'bmg_volunteer' => 'Volunteer'
 ];

 foreach ($tables->options as $value => $text) {
    echo("<option value='$value'>$text</option>");    
 }

如何在对象中一次遍历2个或更多数组

3 个答案: