Question

我想知道如何查询数据库，我可以返回两个总和，第一个是检查总数，然后是每个检查员的总数，即Joe总共进行了4次检查，但仍然显示故障不同层次的。我是sql的新手，所以到目前为止我已经包含了我的脚本，但如果您需要更多信息，请告诉我。

SELECT     InspectorCode AS Inspector, InspectionProcedureName AS [Procedure], COUNT(*) AS     Total
FROM         UnitData_Vehicle
WHERE     (DATEDIFF(day, InspectionDateTime, GETDATE()) = 1)
AND InspectionProcedureName LIKE '%Inspection%'
GROUP BY InspectionProcedureName, InspectorCode

我想看看

Inspector   Procedure   Total    InspTotal 
joe         1 - Inspection  1        4
joe         2 - Inspection  3
kit         3 - Inspection  14       14
hugh        1 - Inspection  17       32
hugh        6 - Inspection  15
mike        4 - Inspection  18       18

Answer 1

我不确定sql server但是oracle跟随查询会得到你想要的结果 -

SELECT zz.Inspector as Inspector,
       zz.Procedure as Procedure,
       zz.total as total,
       case 
       when zz.c_1 =1 then
       zz.InspTotal 
       else 
       null
       end as InspTotal        
       FROM (SELECT InspectorCode AS Inspector, 
       InspectionProcedureName AS Procedure, 
       COUNT(*) AS     Total ,
       count(*) over(partition by InspectorCode) InspTotal,
       row_number() over( partition by InspectorCode order by InspectionProcedureName) c_1 
FROM   UnitData_Vehicle 
WHERE  (DATEDIFF(day, InspectionDateTime, GETDATE()) = 1) 
       AND InspectionProcedureName LIKE '%Inspection%' 
GROUP BY InspectionProcedureName, InspectorCode)zz;

请检查where条件。我正在检查并仅为最后一个所需的列工作.. 如你所知，你没有告诉任何有关条件......

如果您想澄清此查询中的任何内容，请在此处发表评论..

还有一件事 - 我假设你只需要InspTotal列值一次任何InspectorCode代码.. 我是对的吗？

Answer 2

编辑：根据@pratik garg的回答，看起来这样在SQL Server中有效：

select  InspectorCode as Inspector
,       InspectionProcedureName as Procedure
,       count(*) as Total
,       count(*) over (partition by InspectorCode) as InspTotal
from    UnitData_Vehicle as uv1
where   (datediff(day, InspectionDateTime, getdate()) = 1)
        and InspectionProcedureName like '%Inspection%'
group by 
        InspectorCode
,       Procedure

count(*) over (partition by InspectorCode)显然尊重where条款，但确实计入多个组。有意思:)）

Answer 3

以下示例代码适用于我的数据库

SELECT fiscalmonth,item,fiscalyear
       ,SUM(valuesale)
       ,
(SELECT SUM(valueSale)
FROM inbalance b 
WHERE b.fiscalmonth <= a.fiscalmonth 
and a.fiscalyear =b.fiscalyear 
and a.item = b.item
) AS RunningTotal
FROM inbalance a
WHERE a.item='1101'
AND a.fiscalyear=2011
GROUP BY fiscalmonth,item,fiscalyear

通过将我的代码“翻译”到您的查询

SELECT     InspectorCode AS Inspector, InspectionProcedureName AS [Procedure], COUNT(*) AS     Total
, (
SELECT COUNT(*) FROM UnitData_Vehicle b
WHERE a.InspectorCode = b.InspectorCode 
AND b.InspectionProcedureName <=  b.InspectionProcedureName
GROUP BY InspectionProcedureName,InspectorCode
) As InspTotal
FROM         UnitData_Vehicle a
WHERE     (DATEDIFF(day, InspectionDateTime, GETDATE()) = 1)
AND InspectionProcedureName LIKE '%Inspection%'
GROUP BY InspectionProcedureName, InspectorCode

SQL Server 2005，计算总数

3 个答案: