Question

想象一下，我们有一张桌子：

SELECT SUM(A) AS TOTALS,DATE,STUFF FROM TABLE WHERE DATE BETWEEN 'DATESTART' AND 'DATEEND'
GROUP BY DATE,STUFF

通常情况下，总计为：

totals stuff    date
23      x      01.01.1900
3       x      02.01.1900
44      x      06.01.1900

但是如果我们在startdate之前有前面的数据怎么办，我想将这些初始数据添加到我的startdate值;例如;从时间的开始，我已经有一个x的总和值，让我们说100 所以我希望我的表从123开始，并添加以前的数据，如： 123 126 126 + 44等......

totals stuff    date
123      x      01.01.1900
126      x      02.01.1900
170      x      06.01.1900

我如何实现这一目标？

来源数据：

WITH    Stocks
          AS (
               SELECT
                Dep.Dept_No ,
                SUM(DSL.Metre) AS Metre ,
                CONVERT(VARCHAR(10), Date, 112) AS Date
               FROM
                DS (NOLOCK) DSL
                JOIN TBL_Depts (NOLOCK) Dep ON Dep.Dept_No = DSL.Dept
               WHERE
                1 = 1 AND
                DSL.Sil = 0 AND
                DSL.Depo IN ( 5000, 5001, 5002, 5003, 5004, 5014, 5018, 5021, 5101, 5109, 5303 ) AND
                Dep.Dept_No NOT IN ( 6002 ) AND
                Dep.Dept_No IN ( 6000, 6001, 6003, 6004, 6005, 6011, 6024, 6030 ) AND
                DSL.Date BETWEEN '2013-06-19' AND '2013-06-20'
               GROUP BY
                Dep.Dept_No ,
                CONVERT(VARCHAR(10), Date, 112)
             )
    SELECT
        Stocks.Metre ,
        Dep.Dept AS Dept ,
        Stocks.Date
    FROM
        Stocks
        LEFT JOIN TBL_Depts (NOLOCK) Dep ON Stocks.Dept = Dep.Dept
    ORDER BY
        Stocks.Metre DESC

Answer 1

任何具有窗口和分析功能的RDBMS（SQL Server 2012，PostgreSQL但不是MySQL）

SELECT
    SumA + SUM(SumARange) OVER (ORDER BY aDate ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS TOTALS,
    other, aDate
FROM
    (
    SELECT
        SUM(a) AS SumARange,
        other, aDate
    FROM
        SomeTable
    WHERE
        aDate BETWEEN '20130101' AND '20130106'
    GROUP BY
        other, aDate
    ) X
    CROSS JOIN
    (
    SELECT
        SUM(a) AS SumA
    FROM
        SomeTable
    WHERE
        aDate < '20130101'
    ) Y
ORDER BY
    aDate;

或

SELECT
    SUM(SumA) OVER () + SUM(SumARange) OVER (ORDER BY aDate ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS TOTALS,
    other, aDate
FROM
    (
    SELECT
        SUM(CASE WHEN aDate < '20130101' THEN a ELSE 0 END) AS SumA,
        SUM(CASE WHEN aDate BETWEEN '20130101' AND '20130106' THEN a ELSE 0 END) AS SumARange,
        other, aDate
    FROM
        SomeTable
    WHERE
        aDate <= '20130106'
    GROUP BY
        other, aDate
    ) X
ORDER BY
    aDate;

SQLFiddle example和another

Answer 2

使用APPLY运算符选项来计算总计。您还需要在GROUP BY子句中添加其他CASE表达式

;WITH cte AS
(
 SELECT SUM(a) AS sumA, [stuff], MAX([Date]) AS [Date]
 FROM SomeTable
 WHERE [Date] <= '20130106'
 GROUP BY [stuff], CASE WHEN [Date] <= '20130101' THEN 1 ELSE [Date] END
 )
 SELECT o.total, [stuff], [Date]
 FROM cte c CROSS APPLY (
                         SELECT SUM(c2.sumA) AS total
                         FROM cte c2
                         WHERE c.[Date] >= c2.[Date]
                         ) o

请参阅SQLFiddle

上的示例

运行具有初始值的总计，然后添加日期所述的总计

2 个答案: