5000毫秒我正在显示一个对话框解除我的对话框后,吐司应该出现,但不是,为什么我没有得到这个?我怎么能这样做?
总是感谢帮助..!
signin.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
// showDialog(0);
t = new Thread() {
public void run() {
register();
try {
while(counter<1){
showmsg(0);
Thread.sleep(5000);
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
};
t.start();
}
});
}
@Override
protected Dialog onCreateDialog(int id) {
switch (id) {
case 0: {
++counter;
dialog = new ProgressDialog(this);
if(counter==1){
dialog.setMessage("Registering...");
}
else{
Context context = getApplicationContext();
CharSequence text = "Hello toast!";
int duration = Toast.LENGTH_SHORT;
Toast toast = Toast.makeText(context, text, duration);
toast.show();
}
dialog.setIndeterminate(true);
dialog.setCancelable(true);
return dialog;
}
}
return null;
}
public void showmsg(int actionsToBePerformedOnScreen) {
Message msg = new Message();
msg.what = actionsToBePerformedOnScreen;
handler.sendMessage(msg);
}
public Handler handler = new Handler() {
@Override
public void handleMessage(Message msg) {
switch (msg.what) {
case 0:
showDialog(0);
break;
case 1:
// clear all images in the list
removeDialog(0);
break;
}
};
};
答案 0 :(得分:2)
您正试图以onCreateDialog
方法展示您的Toast,并且它以counter!=1
为条件。显示对话框时不会调用onCreateDialog
,但仅在创建对话框时调用。它只被叫一次,因此Toast永远不会出现。
我相信您正在尝试运行该线程,在运行时显示进度并将其解除并在Toast完成时显示Toast。如果是这种情况,实现目标的更简单和正确的方法是使用AsyncTask
。在此处阅读:http://developer.android.com/reference/android/os/AsyncTask.html
随意提出更多问题。