Question

以下逻辑用于转换，以便将字符串列表转换为每个字符串都用引号和逗号分隔

>>> record_hash
['AAA', 'BBB', 'CCC']
>>> t="'"+"','".join(record_hash)+"'"
>>> t
"'AAA','BBB','CCC'"
>>>

此逻辑传递给下面的逻辑以形成SQL语句以形成where column in条件

 def selectAllPackageType(record_hash, severity):
        t="'"+"','".join(record_hash[])+"'"
        joined_string = ', '.join(['"{}"'.format(value) for value in record_hash])
        sql = 'select package_type from slack_jira where severity = ? and  record_hash in (?)'
        print(sql)
        conn = getSQLConnection();
        package_type = []
        conn.set_trace_callback(print)
        if conn is not None:
            cursor = conn.cursor()
            cursor.execute(sql,(severity,t))
            records = cursor.fetchall()
            for row in records:
                package_type.append(row['package_type'])
            cursor.close()
            conn.close()
        else:
            print("Error! cannot perform selectByPackageType.")
        return package_type

conn.set_trace_callback(print)打印此值，因为它包含一个记录，导致获取记录失败

select package_type from slack_jira where severity = 'MEDIUM' and  record_hash in ('''AAAAA'',''CCCC''');

所需要的是形成正确的SQL语句，以正确的转义来创建where column in (?)

select package_type from slack_jira where severity = 'MEDIUM' and  record_hash in ('AAAAA','CCCC');

Answer 1

我知道了，这很有效

result_set = conn.execute("SELECT * FROM slack_jira WHERE severity='MEDIUM' and id IN (%s)" % ','.join('?'*len(record_hash)), record_hash)

>>> import sqlite3
>>> conn = sqlite3.connect('/tmp/test.db')
>>> conn.set_trace_callback(print)
>>> record_hash=['A','B']
>>> result_set = conn.execute("SELECT * FROM slack_jira WHERE severity='MEDIUM' and id IN (%s)" % ','.join('?'*len(record_hash)), record_hash)
SELECT * FROM slack_jira WHERE severity='MEDIUM' and id IN ('A','B')

python如何在逗号分隔的表格中形成列表以逗号分隔

1 个答案: