Question

我正在python的list内获取一些switch命令输出，我能够在list中获取结果，但是该list包含两个元素，即使那些元素也是逗号分隔的，我也想获取那些逗号分隔的值作为的单个元素列表。

我正在使用netmiko模块，其中我使用python在列表中取出一些命令输出。

rules_version = '2';
service cloud.firestore {
  match /databases/{database}/documents {

Answer 1

好像您需要str.split和list.extend

例如：

myList1 = []        
for k in range(len(cli_commands)):
    net_connect.send_command(cli_commands[k])
    vall=net_connect.send_command(cli_commands[k])
    myList1.extend(vall.strip().split(","))
print(myList1)

Answer 2

您将必须.split(',')每个字符串才能获得嵌套列表，然后将其简单化。使用.split()会在每个sub_string的开头和结尾删除多余的空格。

the_list = ['Cisco IOS Software, C2960S Software (C2960S-UNIVERSALK9-M), Version 15.0(2)SE11, RELEASE SOFTWARE (fc3)', 'NAME: "1", DESCR: "WS-C2960S-24TS-L"\nPID: WS-C2960S-24TS-L  , VID: V02  , SN: FOC1452X5C5\n\n']

the_list = [map(lambda x: x.strip(), item.split(',')) for item in the_list]
new_list = [item for sub_list in the_list for item in sub_list]

第一行将the_list内的每个字符串转换为映射生成器，该映射生成器在除以.strip()字符后将','（修剪空格）应用于每个子字符串。第二个只是为了使列表清楚，这是[[1, 2], [3, 4]]将变成[1, 2, 3, 4]。等效于：

the_list = ['Cisco IOS Software, C2960S Software (C2960S-UNIVERSALK9-M), Version 15.0(2)SE11, RELEASE SOFTWARE (fc3)', 'NAME: "1", DESCR: "WS-C2960S-24TS-L"\nPID: WS-C2960S-24TS-L  , VID: V02  , SN: FOC1452X5C5\n\n']

new_list = []
for string in the_list:
    for item in string.split(','):
        new_list.append(item.strip())

Answer 3

绝对毁灭的答案是正确的，但您必须像这样使用它

myList = ['Cisco IOS Software, C2960S Software (C2960S-UNIVERSALK9-M), Version 15.0(2)SE11, RELEASE SOFTWARE (fc3)', 'NAME: "1", DESCR: "WS-C2960S-24TS-L"\nPID: WS-C2960S-24TS-L  , VID: V02  , SN: FOC1452X5C5\n\n']

cs_mylist = []
for y in [x.split(',') for x in myList]:
    for z in y:
        cs_mylist.append(z)

print(cs_mylist)

如何在列表中分隔逗号分隔的值以使其成为列表的单个值

3 个答案: