Question

从下表中我如何获得过去几天销售额> gt = = 50％的商品？

date        item_id  in_stock  out-stock
2011-06-20    352       50        30
2011-06-21    351       10        1
2011-06-22    332       23        20
2011-06-23    311       12         7

目前我正在使用一个计算销售百分比的查询，并使用php我循环浏览每件商品，并获得销售额超过50％的商品。

SELECT i.id as item_id,i.item,SUM(dpr.out_stock)/SUM(dpr.in_stock) * 100 as p,SUM(dpr.out_stock) as sales,u.title as unit,u.id as unit_id   
     FROM `sm_daily_item_stock_report` as dpr
  INNER JOIN sm_item_master as i on dpr.item_id=i.id and i.consumable='1'
  INNER JOIN sm_unit_master as u on i.primary_unit=u.id
  WHERE date between '2011-06-20' and '2011-06-23'
  and dpr.store_id='1' GROUP BY item_id

但是此查询会针对store_id 1返回所有产品。

Krishnik

Answer 1

将HAVING p > 50添加到查询中：）

Answer 2

SELECT i.id as item_id,i.item,SUM(dpr.out_stock)/SUM(dpr.in_stock) * 100 as p,SUM(dpr.out_stock) as sales,u.title as unit,u.id as unit_id   
FROM `sm_daily_item_stock_report` as dpr
INNER JOIN sm_item_master as i on dpr.item_id=i.id and i.consumable='1'
INNER JOIN sm_unit_master as u on i.primary_unit=u.id
WHERE date between '2011-06-20' and '2011-06-23'
and dpr.store_id='1' GROUP BY item_id
having (SUM(dpr.out_stock)/SUM(dpr.in_stock) * 100) > 50

MySql查询：获取销售额＆gt; =某个百分比的项目

2 个答案: