Question

我尝试计算2个表中的项目百分比。

表：

operation_systems
id   | title
1001 | Windows
1002 | Apple
1003 | Linux

sub_pref
sub_id | id   | user_id
1      | 1001 | 1
2      | 1001 | 2
3      | 1003 | 1
4      | 1003 | 2
5      | 1003 | 1
6      | 1003 | 2
7      | 1003 | 3
8      | 1003 | 4
9      | 1003 | 5
10     | 1002 | 5

使用以下查询：

SELECT operation_systems.id, operation_systems.title,
COUNT(sub_pref.id) AS count, ROUND( SUM( 100 ) / total ) AS percentage
FROM operation_systems
CROSS JOIN (SELECT COUNT( * ) AS total FROM operation_systems)x
LEFT JOIN sub_pref ON sub_pref.id = operation_systems.id
GROUP BY operation_systems.id
ORDER BY count DESC;

目前的结果：

Apple   | 1 | 33%
Windows | 2 | 33%
Linux   | 7 | 33%

期望的结果：

Apple   | 1 | 10%
Windows | 2 | 20%
Linux   | 7 | 70%

如何获得正确的百分比？

Answer 1

错误在于这部分代码：

SELECT COUNT( * ) AS total FROM operation_systems

这将为您提供operation_systems的总数，即3，而不是sub_pref中引用每个operation_system的总行数。结果你得到33％的百分比，因为你只是将100除以3，三次。

如果您改变思考方式，这个问题就更容易解决了。您当前正在从operation_systems中进行选择，然后从sub_pref将数据提取到您的查询中。但是，您真正想要做的是在sub_pref中聚合数据，然后从operation_systems为每个结果提供一个友好名称。

我建议：

SELECT operation_systems.title,
       COUNT(sub_pref.id) AS COUNT,
       ROUND(COUNT(sub_pref.id) * 100 /
               (SELECT COUNT(*)
                FROM sub_pref)) AS percentage
FROM sub_pref
LEFT JOIN operation_systems ON operation_systems.id = sub_pref.id
GROUP BY sub_pref.id
ORDER BY COUNT DESC

我创建了an sqlfiddle，其中包含您提供的架构/数据以及上述解决方案。只需点击＆＃34;运行SQL＆＃34;看它是否有效。

Answer 2

试试这个：

SELECT os.id, os.title, sp.num_sp, os_total.total, ((sp.num_sp / os_total.total) * 100)
FROM operation_systems os
JOIN (
    SELECT id as os_id, COUNT(*) as num_sp
    FROM sub_pref
    GROUP BY id
) sp ON os.id = sp.os_id
CROSS JOIN (
    SELECT COUNT(*) as total
    FROM sub_pref
) os_total

Answer 3

这是一个易于阅读的查询：

SELECT title, (COUNT(sub_pref.id) / t.total) * 100 AS percent
FROM operation_systems, sub_pref, (SELECT COUNT(*) AS total FROM sub_pref) t
WHERE operation_systems.id = sub_pref.id
GROUP BY sub_pref.id
ORDER BY percent

工作演示：http://sqlfiddle.com/#!2/ab661/3

Answer 4

实现它的另一种方式

select 
os.id,
os.title,
ROUND( ( cnt / ( select count(*) from sub_pref )*100) ) as percentage
from operation_systems os
inner join (
    select id,count(id) as cnt from sub_pref 
    group by id
)sp
on sp.id = os.id
group by os.id
order by os.title

http://sqlfiddle.com/#!2/4bc0b/21

计算物品并获得百分比

4 个答案: