Question

几周前我问了一个类似的问题，但现在要求已经改变了。

考虑以下表格： http://www.maroisconsulting.com/Temp/query.png

我需要创建一个查询，该查询返回经理（Titles.IsManager）员工的百分比以及在认证字段（Employees.Certified）中有日期的人员。结果需要按每个商店所在的集团进行分组。

到目前为止，我有这个：

SELECT d.GroupId, 
       Sum(d.cert_complete) AS SumOfcert_complete, 
       Count(d.cert_complete) AS CountOfcert_complete
FROM (SELECT DISTINCT
        s.GroupId,
        e.EmployeeID,
        IIf(e.Certified Is Null,0,1) AS cert_complete
    FROM
        ((Stores AS s
        INNER JOIN EmployeeStores AS es ON s.StoreId = es.StoreId)
        INNER JOIN Employees AS e ON es.EmployeeId = e.EmployeeID)
        INNER JOIN Titles AS t ON e.TitleId = t.TitleId
    )  AS d
WHERE t.IsManager
GROUP BY d.GroupId;

然后这个

SELECT q.GroupId, 
      (SumOfcert_complete/CountOfcert_complete)*100 AS percent_certified, 
      Groups.GroupName
FROM qryGroupCert_base AS q 
INNER JOIN Groups ON q.GroupId = Groups.GroupId;

您可以在第一个查询中看到我添加了标题表。

1）我被提示输入IsManager，虽然我不知道为什么 2）返回的结果与我添加IsManager

之前的结果没有什么不同

有人在这里看到了什么问题吗？

非常感谢

Answer 1

也许您需要为t.IsManager提供标准，例如t.IsManager = TRUE。如果where子句没有设置值等于的值，则Access可能不会将其解析为实际列，但认为它是查询参数。

Answer 2

在第一个查询中，您有此子查询，其中包含别名为“t”的标题：

(SELECT DISTINCT
    s.GroupId,
    e.EmployeeID,
    IIf(e.Certified Is Null,0,1) AS cert_complete
FROM
    ((Stores AS s
    INNER JOIN EmployeeStores AS es ON s.StoreId = es.StoreId)
    INNER JOIN Employees AS e ON es.EmployeeId = e.EmployeeID)
    INNER JOIN Titles AS t ON e.TitleId = t.TitleId
)  AS d

然后，在子查询的定义之后，你有了这个WHERE子句：

WHERE t.IsManager

问题是“t”别名和IsManager列只存在于子查询中 - ＆gt;它们对于外（父）查询是未知的。如果Access数据库引擎遇到无法识别为对象名称，函数，文字值或SQL关键字的内容，则认为某些内容必须是参数...因此弹出输入框，要求您提供（IsManager）参数的值。

我认为你应该在子查询定义中移动WHERE子句。

SELECT d.GroupId, 
       Sum(d.cert_complete) AS SumOfcert_complete, 
       Count(d.cert_complete) AS CountOfcert_complete
FROM [SELECT DISTINCT
        s.GroupId,
        e.EmployeeID,
        IIf(e.Certified Is Null,0,1) AS cert_complete
    FROM
        ((Stores AS s
        INNER JOIN EmployeeStores AS es ON s.StoreId = es.StoreId)
        INNER JOIN Employees AS e ON es.EmployeeId = e.EmployeeID)
        INNER JOIN Titles AS t ON e.TitleId = t.TitleId
        WHERE t.IsManager = True
    ]. AS d
GROUP BY d.GroupId;

计算认证经理的百分比

2 个答案: