在嵌套对象数组猫鼬中排序

时间:2020-10-26 02:37:35

标签: node.js mongodb mongoose

{
  "_id": "5f8e51e188e8bc24ff8b85e4",
  "name": "stars",
  "players": [
    {
      "_id": "5f961d850965854110fce6a5",
      "name": "juliannn",
      "points": 0
    },
    {
      "_id": "5f961dec0965854110fce6a6",
      "name": "Julian",
      "points": 0
    },
    {
      "_id": "5f961df70965854110fce6a7",
      "name": "Matias",
      "points": 0
    },
    {
      "_id": "5f961e070965854110fce6a8",
      "name": "Mariano",
      "points": 11
    }
  ],
  "description": "Pick 1 or more numbers that sum to the number of stars",
  "__v": 0
}

我有此函数返回的数据集合

const game = await Game.findOne({ name: id })

现在我想按DESC得分对球员进行排序,而我所做的是

const game = await Game.findOne({ name: id }).sort({'players.points': 1})

我从here那里得到了

我期望的是这个

{
  "_id": "5f8e51e188e8bc24ff8b85e4",
  "name": "stars",
  "players": [
    {
      "_id": "5f961e070965854110fce6a8",
      "name": "Mariano",
      "points": 11
    },
    {
      "_id": "5f961d850965854110fce6a5",
      "name": "juliannn",
      "points": 0
    },
    {
      "_id": "5f961dec0965854110fce6a6",
      "name": "Julian",
      "points": 0
    },
    {
      "_id": "5f961df70965854110fce6a7",
      "name": "Matias",
      "points": 0
    }
  ],
  "description": "Pick 1 or more numbers that sum to the number of stars",
  "__v": 0
}

我想念什么吗?

1 个答案:

答案 0 :(得分:0)

您需要使用聚合操作数组。

db.collection.aggregate([
  {
    $match: {
      _id: "5f8e51e188e8bc24ff8b85e4"
    }
  },
  {
    $unwind: "$players"
  },
  {
    $sort: {
      "players.points": -1
    }
  },
  {
    $group: {
      _id: "$_id",
      name: {
        $first: "$name"
      },
      players: {
        $push: "$players"
      }
    }
  }
])

工作Mongo playground