删除节点的所有子节点

Question

我有一个DOM文档节点。如何删除其所有子节点？例如：

<employee> 
     <one/>
     <two/>
     <three/>
 </employee>

变为：

   <employee>
   </employee>

我想删除employee的所有子节点。

Answer 1

无需删除子节点的子节点

public static void removeChilds(Node node) {
    while (node.hasChildNodes())
        node.removeChild(node.getFirstChild());
}

Answer 2

public static void removeAllChildren(Node node)
{
  for (Node child; (child = node.getFirstChild()) != null; node.removeChild(child));
}

Answer 3

public static void removeAllChildren(Node node) {
    NodeList nodeList = node.getChildNodes();
    int i = 0;
    do {
        Node item = nodeList.item(i);
        if (item.hasChildNodes()) {
            removeAllChildren(item);
            i--;
        }
        node.removeChild(item);
        i++;
    } while (i < nodeList.getLength());
}

Answer 4

只需使用：

Node result = node.cloneNode(false);

作为文档：

Node cloneNode(boolean deep)
deep - If true, recursively clone the subtree under the specified node; if false, clone only the node itself (and its attributes, if it is an Element).

Answer 5

    public static void removeAll(Node node) 
    {
        for(Node n : node.getChildNodes())
        {
            if(n.hasChildNodes()) //edit to remove children of children
            {
              removeAll(n);
              node.removeChild(n);
            }
            else
              node.removeChild(n);
        }
    }
}

这将通过传递员工节点来删除节点的所有子元素。

Answer 6

private static void removeAllChildNodes(Node node) {
    NodeList childNodes = node.getChildNodes();
    int length = childNodes.getLength();
    for (int i = 0; i < length; i++) {
        Node childNode = childNodes.item(i);
        if(childNode instanceof Element) {
            if(childNode.hasChildNodes()) {
                removeAllChildNodes(childNode);                
            }        
            node.removeChild(childNode);  
        }
    }
}