删除根节点,但保留所有子节点

时间:2019-06-18 06:35:05

标签: c# xml linq-to-xml element xmldocument

我有通过

解析的xml
<ns0:Root xmlns:ns0="http://Core.Schemas.SouCurrencyRate">
    <Test>
        <CurrencyCode>SEKAUDPMI</CurrencyCode>
        <CurrencyType>AUD</CurrencyType>
        <CurrencyDate>2019 Juni</CurrencyDate>
        <CurrencyRate>6.5656</CurrencyRate>
        <RecordCreated>2019-06-30</RecordCreated>
        <RecordCreatedSOP>2019-06-01</RecordCreatedSOP>
    </Test>
    <Test>
        <CurrencyCode>SEKBRLPMI</CurrencyCode>
        <CurrencyType>BRL</CurrencyType>
        <CurrencyDate>2019 Juni</CurrencyDate>
        <CurrencyRate>2.4376</CurrencyRate>
        <RecordCreated>2019-06-30</RecordCreated>
        <RecordCreatedSOP>2019-06-01</RecordCreatedSOP>
    </Test>
    <Test>
        <CurrencyCode>SEKCADPMI</CurrencyCode>
        <CurrencyType>CAD</CurrencyType>
        <CurrencyDate>2019 Juni</CurrencyDate>
        <CurrencyRate>7.0771</CurrencyRate>
        <RecordCreated>2019-06-30</RecordCreated>
        <RecordCreatedSOP>2019-06-01</RecordCreatedSOP>
    </Test>
    <Test>
        <CurrencyCode>SEKCHFPMI</CurrencyCode>
        <CurrencyType>CHF</CurrencyType>
        <CurrencyDate>2019 Juni</CurrencyDate>
        <CurrencyRate>951.7346</CurrencyRate>
        <RecordCreated>2019-06-30</RecordCreated>
        <RecordCreatedSOP>2019-06-01</RecordCreatedSOP>
    </Test>
</ns0:Root>

该xml具有(“ Test”)子节点,这些子节点经常出现。 我需要做的实际上是删除(" <ns0:Root xmlns:ns0="http://Core.Schemas.SouCurrencyRate"> ")

这样XML输出是

<Test>
    <CurrencyCode>SEKAUDPMI</CurrencyCode>
    <CurrencyType>AUD</CurrencyType>
    <CurrencyDate>2019 Juni</CurrencyDate>
    <CurrencyRate>6.5656</CurrencyRate>
    <RecordCreated>2019-06-30</RecordCreated>
    <RecordCreatedSOP>2019-06-01</RecordCreatedSOP>
</Test>
<Test>
    <CurrencyCode>SEKBRLPMI</CurrencyCode>
    <CurrencyType>BRL</CurrencyType>
    <CurrencyDate>2019 Juni</CurrencyDate>
    <CurrencyRate>2.4376</CurrencyRate>
    <RecordCreated>2019-06-30</RecordCreated>
    <RecordCreatedSOP>2019-06-01</RecordCreatedSOP>
</Test>

我试图做的是

    System.Xml.XmlDocument xDoc = new System.Xml.XmlDocument();
    xDoc.Load(bizobj.Message.BodyPart.GetOriginalDataStream());


    System.Xml.XmlNode xNode = xDoc.FirstChild;
    System.Xml.XmlNode xParent = xNode.ParentNode;
    System.Xml.XmlNodeList xChilds = xNode.ChildNodes;
    xDoc.RemoveChild(xNode);
    foreach (System.Xml.XmlNode node in xChilds)
    {
        xParent.AppendChild(node);
    }

但是主要的问题是返回的xml仅包含一个孩子(“测试”),而没有其他孩子。

我还尝试使用Linq在帖子中找到它的地方

XDocument input = XDocument.Load("input.xml");
XElement firstChild = input.Root.Elements().First();

但这会返回相同的内容,对我的情况没有帮助。

有人可以在正确的方向帮助我吗?

谢谢。

2 个答案:

答案 0 :(得分:1)

如果您真的只需要文本字符串,最快的方法是在Root XElement上使用XmlReader:

XDocument xDoc = XDocument.Parse(bizobj.Message.BodyPart.GetOriginalDataStream());
XElement root = xDoc.Root;
XmlReader reader = root.CreateReader();
reader.MoveToContent();
string txt = reader.ReadInnerXml();

答案 1 :(得分:0)

如果有人想看看并使用它,只需将我的最终代码放在这里。 无论如何,菲尔伯特还是把我扔向正确方向的那个人。

 System.Xml.XmlDocument xDoc = new System.Xml.XmlDocument();
        xDoc.Load(bizobj.Message.BodyPart.GetOriginalDataStream());
        string output = xDoc.DocumentElement.InnerXml;
    byte[] byteArray = Encoding.ASCII.GetBytes(output);
    MemoryStream stream = new MemoryStream(byteArray);

    stream.Position = 0;
    bizobj.Message.BodyPart.Data = stream;


    return bizobj;