如何将这个嵌套的if语句转换为更易读和更优雅的东西?
if(speed==0){
othvalue=0;
}else {
if(speed>value1864cmn){
othvalue=value1864cmn;
}else {
if(speed>value1746cmn){
othvalue=value1746cmn;
}else {
if(speed>value1628cmn){
othvalue=value1628cmn;
}else {
if(speed>value1510cmn){
othvalue=value1510cmn;
}else {
if(speed>value1392cmn){
othvalue=value1392cmn;
}else {
if(speed>value1274cmn){
othvalue=value1274cmn;
}else {
if(speed>value1156cmn){
othvalue=value1156cmn;
}else {
if(speed>value1038cmn){
othvalue=value1038cmn;
}else {
if(speed>value920cmn){
othvalue=value920cmn;
}
}
}
}
}
}
}
}
}
};
答案 0 :(得分:5)
您可以使用“匹配”构造:
var othvalue = (speed == 0) ? 0
: (speed <= 10) ? 10
: (speed <= 20) ? 20
: (speed <= 30) ? 30
: 40;
答案 1 :(得分:3)
您不需要嵌套它,也不需要将其转换为switch语句。只需将if
放在else
旁边。
例如:
if(speed==0){
othvalue=0;
} else if(speed>value1864cmn){
othvalue=value1864cmn;
} else if {
...
答案 2 :(得分:1)
if (speed == 0) {
othvalue = 0;
} else if (speed > value1864cmn) {
othvalue = value1864cmn;
} else if (speed > value1746cmn) {
othvalue = value1746cmn;
} else if (speed > value1628cmn) {
othvalue = value1628cmn;
} else if (speed > value1510cmn) {
othvalue = value1510cmn;
} else if (speed > value1392cmn) {
othvalue = value1392cmn;
} else if (speed > value1274cmn) {
othvalue = value1274cmn;
} else if (speed > value1156cmn) {
othvalue = value1156cmn;
} else if (speed > value1038cmn) {
othvalue = value1038cmn;
} else if (speed > value920cmn) {
othvalue = value920cmn;
};
答案 3 :(得分:1)
if (speed == 0) {
othvalue = 0;
} else {
var values = [
value1746cmn, value1628cmn, value1510cmn, value1392cmn, value1274cmn,
value1156cmn, value1038cmn, value920cmn
];
for (var i in values) {
if (speed > values[i]) {
othvalue = values[i];
break;
}
}
}
答案 4 :(得分:1)
//我不知道优雅,但是通过一个数组非常快。
function setSpeedValue(speed){
var L= 9, values= [0, 920, 1038, 1156, 1274, 1392, 1510, 1628, 1746, 1864];
while(values[L]>speed)--L;
return 'value'+values[L]+'cmn';
}
alert(setSpeedValue(1040))