Question

很酷的是Rebol的PARSE方言足够概括，它可以在符号结构和字符串上进行模式匹配和提取。像这样：

; match a single "a" character, followed by any number of "b" chars
>> string-rule: ["a" some "b"]

>> parse "abb" string-rule
== true
>> parse "aab" string-rule
== false

; look for a single apple symbol, followed by any number of bananas
>> block-rule: ['apple some 'banana]

>> parse [apple banana banana] block-rule
== true
>> parse [apple apple banana] block-rule
== false

但是，假设我正在寻找一个包含苹果符号的块，然后找到与string-rule匹配的任意数量的字符串：

; test 1
>> parse [apple "ab" "abbbbb"] mixed-rule
== true

; test 2
>> parse [apple "aaaa" "abb"] mixed-rule
== false

; test 3
>> parse [banana "abb" "abbb"] mixed-rule
== false

我如何制定这样的mixed-rule？查看文档，它表明可以使用INTO：

http://www.rebol.net/wiki/Parse_Project#INTO

看似自然的答案似乎不起作用：

>> mixed-rule: ['apple some [string! into ["a" some "b"]]]

当它通过测试1并且正确地为测试3返回false时，它在测试2中错误地返回true。这是我的错误还是Rebol中的错误（我正在使用r3 A111）？

Answer 1

对REBOL3 forum提出异议建议：

only the second string is checked.
Should be:
    ['apple some [and string! into ["a" some "b" ]]]

如何在同一规则中将字符串解析和块解析混合在一起？

1 个答案: