理解学说的问题2

时间:2011-06-17 22:14:44

标签: doctrine doctrine-orm

我很难弄清楚如何正确使用Doctrine 2和zend框架。我正在阅读文档并基于我迄今为止所做的和zendcasts。当我尝试用我的数据库做关系时,问题实际上就开始了,因为我不太确定如何使用doctrine集合。在我的测试用例中,我有一个用户实体:

class User 
{
/**
 * @var integer
 * @Column (name="id", type="integer", nullable=false)
 * @Id
 * @GenerateValue(strategy="IDENTIY")
 * 
 */
private $id;

/**
 * @Column(type="string",length=60,nullable=true)
 * @var string
 */
private $email;

/**
 * 
 * @param \Doctring\Common\Collections\Collection $property
 * @OneToMany(targetEntity="Countries",mappedBy="user", cascade={"persist", "remove"})
 */
private $countries;

public function __get($property) 
{
    return $this->$property;
}

public function __set($property, $value)
{
    $this->$property = $value;
}
}

与国家实体有关:

class Countries {
/**
 * @var integer
 * @Column (name="id", type="integer", nullable=false)
 * @Id
 * @GenerateValue(strategy="IDENTIY")
 * 
 */
private $id;

/**
 *
 * @var string
 * @Column(type="string") 
 */
private $countryName;

/**
 *
 * @var User
 * @ManyToOne(targetEntity="User") 
 * @JoinColumns({
 *  @JoinColumn(name="user_id", referencedColumnName="id")
 * })
 */
private $user;


public function __get($property) 
{
    return $this->$property;
}

public function __set($property, $value)
{
    $this->$property = $value;
}
}

现在我可以从控制器分配这样的国家:

    $p1 = new \Federico\Entity\Countries();
    $p1->countryName = 'Argentina';
    $p2 = new \Federico\Entity\Countries();
    $p2->countryName = 'España';
    $u = new \Federico\Entity\User();
    $u->firstname = 'John';
    $u->lastname = 'Doe';
    $u->id = 1;

会告诉我这个对象:

object(Federico\Entity\User)[109]
  private 'id' => int 1
  private 'email' => null
  private 'countries' => 
array
  0 => 
    object(Federico\Entity\Countries)[107]
      private 'id' => null
      private 'countryName' => string 'Argentina' (length=9)
      private 'user' => null
  1 => 
    object(Federico\Entity\Countries)[108]
      private 'id' => null
      private 'countryName' => string 'España' (length=7)
      private 'user' => null
  public 'firstname' => string 'John' (length=4)
  public 'lastname' => string 'Doe' (length=3)

如果您注意这一点,您会看到国家/地区对象中的用户属性设置为null。我不明白这是否应该是这样发生的。此外,由于用户将被允许从复选框列表中选择国家/地区,并且他们将能够选择多个国家/地区,...不应该以某种方式将国家/地区存储在Db中吗?

2 个答案:

答案 0 :(得分:0)

我看不到您在代码中为用户分配国家/地区的位置。无论如何,你需要做两件事:

在“用户”构造函数中将$countries变量初始化为新的Doctrine\Common\Collections\ArrayCollection

手动将国家/地区与用户连接:

public function addCountry(Country $c)
{
  if (!$this->countries->contains($c)) {
    $this->countries->add($c);
    $c->user = $user;
  }
}

答案 1 :(得分:0)

在学说2中,不鼓励使用魔法吸气剂和制定者。如您所见,它们可能会导致管理关联的问题。以下是如何管理您的用户实体中的关联的示例。

namespace Whatever/Your/Namespace/Is;

use \Doctrine\Common\ArrayCollection;

class User
{
    /**
     * @Column (type="integer")
     * @Id
     * @var integer
     */
     private $id;

     /**
      * @OneToMany(targetEntity="Country", mappedBy="user", cascade={"persist", "remove"})
      * @var ArrayCollection
     private $countries;

     public function __construct()
     {
         $this->countries = new ArrayCollection();
     }

     public function getCountries()
     {
         return $this->countries;
     }

     public function setCountry(Country $country)
     {
         $this->country[] = $country;
         $country->setUser($this);
         return $this;
     }

     public function removeCountry(Country $country)
     {
         return $this->country->removeElement($country);
     }
}

和国家

class Country
{
    /**
     * @Id
     * @Column(type="integer")
     * @var integer
     */
    private $id;

    /**
     * @Column(length=100)
     * @var string
     */
    private $country_name;

    /**
     * @ManyToOne(targetEntity="User", inversedBy="countries")
     * @var User
     */
    private $user;

    public function setUser(User $user)
    {
        $this->user = $user;
        return $this;
    }

    public function getUser()
    {
        return $this->user;
    }

    // ...
}