Question

我正在尝试捕获ARM模板输出，并将其传递到下一步运行的Azure Powershell脚本中。为此，我正在执行以下步骤，所有这些步骤都使用Azure DevOps完成。

在ARM模板中声明输出。

 "outputs": {
    "adminUsername": {
        "type": "string",
        "value": "[parameters('adminUsername')]"
    },
     "virtualMachineName": {
         "value": "[parameters('virtualMachineName')]",
         "type": "string"
        }
}

将ARM模板输出传递到第一个Azure Powershell脚本中，以将每个输出值声明为管道变量。因此可以在我的下一个任务中使用。

    function Convert-ArmOutputToPsObject {
      param (
        [Parameter(Mandatory=$true)]
        [string]
        $ArmOutputString
      )
      if ($PSBoundParameters['Verbose']) {
        Write-Host "Arm output json is:"
        Write-Host $ArmOutputString
      }
      $armOutputObj = $ArmOutputString | ConvertFrom-Json
      $armOutputObj.PSObject.Properties | ForEach-Object {
          $type = ($_.value.type).ToLower()
          $keyname = "ArmOutputs.$($_.name)"
          $value = $_.value.value

          if ($type -eq "securestring") {
              Write-Host "##vso[task.setvariable variable=$keyname;issecret=true]$value"
              Write-Host "Added Azure DevOps secret variable '$keyname' ('$type')"
          } elseif ($type -eq "string") {
              Write-Host "##vso[task.setvariable variable=$keyname]$value"
              Write-Host "Set environment variable to ($env:$keyname)"
              Get-ChildItem Env:
              Write-Host "ARMoutput Id ($keyname)
          } else {
              Throw "Type '$type' is not supported for '$keyname'"
          }
      }
    }
    Convert-ArmOutputToPsObject -ArmOutputString '$(ArmOutputs)' -Verbose

以上脚本的输出成功：从中我可以看到管道变量已设置并可用

Arm output json is:
{"adminUsername":{"type":"String","value":"azureuser"},"virtualMachineName":{"type":"String","value":"vm-test"}}
**##[debug]Processed: ##vso[task.setvariable variable=adminUsername;isOutput=true]azureuser**
Added Azure DevOps variable 'adminUsername' ('string') with value 'azureuser'
##[debug]Processed: ##vso[task.setvariable variable=virtualMachineName;isOutput=true]vm-test
Added Azure DevOps variable 'virtualMachineName' ('string') with value 'vm-test'

我试图在我的第二个Azure powershell脚本中使用上面创建的管道变量“ virtualMachineName”作为参数。

function Disk-encryption {
                                param (
                                [Parameter(Mandatory=$true)]
                                [string]
                                $virtualMachineName)
write-host $virtualMachineName
}
Disk-encryption -virtualMachineName '$(virtualMachineName)'

执行此脚本会引发以下错误

错误：

Line |
   2 | Disk-encryption -virtualMachineName $(virtualMachineName)
     |                                   ~~~~~~~~~~~~~~~~~~
     | The term 'virtualMachineName' is not recognized as the name of
     | a cmdlet, function, script file, or operable program. Check
     | the spelling of the name, or if a path was included, verify
     | that the path is correct and try again.

即使只是尝试仅打印'write-host $ virtualMachineName'，但也会出现相同的错误。似乎$ virutalMachineName不能用作管道变量。

有人可以帮忙吗？我的问题是 1.是否已成功执行任务，因此在管道中是否设置了管道变量并在全局范围内可用？ 2.如果是这样，如何在第二个Azure Powershell脚本中使用新创建的管道变量？

Answer 1

您应该使用输出变量而不是普通变量（请参见https://docs.microsoft.com/en-us/azure/devops/pipelines/process/variables?view=azure-devops&tabs=yaml%2Cbatch#use-output-variables-from-tasks）。

还要看一下https://adamtheautomator.com/arm-output-variables-in-azure-pipelines-powershell/。它完美地解释了如何执行此操作。

将ARM模板输出作为管道变量传递到Azure Powershell任务时出现的问题

1 个答案: