Question

假设我们有2个链接的手臂模板及其关联的*.params.json文件：

createAppServiceTemplate.json
createAppServiceTemplate.params.json
createSqlDbTemplate.json
createSqlDbTemplate.params.json

第二个模板createSqlDbTemplate.json具有输出：

 "outputs": {
        "connectionString": {
            "type": "string",
            "value": "[concat('Database=', parameters('databaseName'), ';Server=', reference(resourceId('Microsoft.DBforPostgreSQL/servers',parameters('serverName')), '2017-12-01').fullyQualifiedDomainName, ';User Id=', parameters('administratorLogin'),'@', parameters('serverName'),';Password=', parameters('administratorPassword'))]"
        }
    }

我将不提取此输出变量并将其作为参数传递给createAppServiceTemplate.params.json。

我尝试将其添加到我的计算机中：

"parameters": {
    "usersDbConnectionString": {
          "value": "[reference('createSqlDbTemplate').outputs.connectionString.value]"
    }
 }

但是我认为参数不能计算表达式？如何实现所需的行为？

Answer 1

假设您下面有链接的createSqlServerTemplate.json模板：

{
  "$schema": "https://schema.management.azure.com/schemas/2019-04-01/deploymentTemplate.json#",
  "contentVersion": "1.0.0.0",
  "parameters": {},
  "variables": {},
  "resources": [],
  "outputs": {
    "greetingMessage": {
      "value": "Hello World",
      "type" : "string"
    }
  }
}

主模板部署链接的模板并获取返回的值。请注意，它按名称引用部署资源，并且使用链接模板返回的属性的名称。

main-template.json：

{
  "$schema": "https://schema.management.azure.com/schemas/2019-04-01/deploymentTemplate.json#",
  "contentVersion": "1.0.0.0",
  "parameters": {},
  "variables": {},
  "resources": [
    {
      "type": "Microsoft.Resources/deployments",
      "apiVersion": "2019-10-01",
      "name": "createAppServiceTemplate",
      "properties": {
        "mode": "Incremental",
        "templateLink": {
          "uri": "[uri(deployment().properties.templateLink.uri, 'createAppServiceTemplate.json')]",
          "contentVersion": "1.0.0.0"
        },
        "parameters": {
           "userDbConnectionString: {
              value: "[reference('createSqlServerTemplate').outputs.greetingMessage.value]"
           }
        }
      }
    },
    {
      "type": "Microsoft.Resources/deployments",
      "apiVersion": "2019-10-01",
      "name": "createSqlServerTemplate",
      "properties": {
        "mode": "Incremental",
        "templateLink": {
          "uri": "[uri(deployment().properties.templateLink.uri, 'createSqlServerTemplate.json')]",
          "contentVersion": "1.0.0.0"
        }
      }
    }
  ]
}

Reference

Azure ARM模板-如何将链接模板的输出变量作为参数传递给另一个模板？

1 个答案: