using Org.BouncyCastle.Math;
string p = "E7A69EBDF105F2A6BBDEAD7E798F76A209AD73FB466431E2E7352ED262F8C558F10BEFEA977DE9E21DCEE9B04D245F300ECCBBA03E72630556D011023F9E857F";
BigInteger P= new BigInteger(p);
抛出异常
System.FormatException: Input string was not in a correct format.
at System.Number.StringToNumber(String str, NumberStyles options, NumberBuffe
r& number, NumberFormatInfo info, Boolean parseDecimal)
at System.Number.ParseInt32(String s, NumberStyles style, NumberFormatInfo in
fo)
at System.Int32.Parse(String s, NumberStyles style)
at Org.BouncyCastle.Math.BigInteger..ctor(String str, Int32 radix)
at Org.BouncyCastle.Math.BigInteger..ctor(String value)
这里有什么问题?
答案 0 :(得分:3)
如果你的数字字符串是十六进制的,你需要在构造函数中指定基数:
BigInteger P = new BigInteger(p,16);