Question

每当我的表单1尝试打开表单2时，我都会收到此错误...

An unhandled exception of type 'System.FormatException' occurred in mscorlib.dll

Additional information: Input string was not in a correct format.

这是什么意思？这是我用来打开Form2的代码......

if (TimerValue == 5000)
         {
             this -> timer1 -> Stop();
             TimerValue = 0;
             Form2 ^ f2 = gcnew Form2;
             f2->Show();
             MoviePlay = 1;
             StreamWriter^ outFile = gcnew StreamWriter("Movie.txt");
             String^ Movie = MoviePlay.ToString();
             outFile->Write(Movie);
             outFile->Close();
             this -> button4 ->Visible = false;
             this -> button5 ->Visible = false;
             this -> label2 ->Visible = false;
             this -> button2 ->Visible = false;
             this -> button3 ->Visible = false;
             FriendString = File::ReadAllText(".\\Rca13\\Friend.txt");
             Friend = System::Convert::ToInt32(FriendString);
             if (Friend == 1)
             {
             this -> pictureBox1 -> Load("RetaliationBackground1_Pony1");
             }
             if (Friend == 2)
             {
             this -> pictureBox1 -> Load("RetaliationBackground1_Pony2");
             }
             if (Friend == 3)
             {
             this -> pictureBox1 -> Load("RetaliationBackground1_Pony3");
             }
             if (Friend == 4)
             {
             this -> pictureBox1 -> Load("RetaliationBackground1_SwagMasta");
             }

         }

此代码中是否有任何内容导致错误？

Answer 1

我怀疑问题是这样的：

Friend = System::Convert::ToInt32(FriendString);

我的猜测是FriendString不是有效整数。如果这是用户输入，您应该使用Int32.TryParse，这样您就可以在不诉诸异常的情况下检测到这一点。

学习读取堆栈跟踪以查看哪个方法失败以及代码中的最后一个位置是非常重要的......然后进一步诊断出问题。

什么“mscorlib.dll中发生了'System.FormatException'类型未处理的异常”是什么意思？

1 个答案: