如何避免在React中重新渲染组件?

时间:2020-08-25 09:25:40

标签: javascript reactjs redux

使用React和Redux创建一个简单的应用程序。

关键是要从服务器获取照片,然后将它们显示出来,如果您单击包含更大照片和评论的照片显示模态窗口。

App组件的代码

import React, { useEffect } from 'react'
import { useSelector, useDispatch } from 'react-redux'
import './App.scss'
import List from './components/list/List'
import Header from './components/header/Header'
import Footer from './components/footer/Footer'
import ModalContainer from './containers/ModalContainer'
import { getPhotos, openModal } from './redux/actions/actions'

const App = () => {

  const { isFetching, error } = useSelector(({ photos }) => photos)
  const photos = useSelector(({ photos }) => photos.photos)
  const { isOpen } = useSelector(({ modal }) => modal)
  const dispatch = useDispatch()
  
  useEffect(() => {
    dispatch(getPhotos())
  }, [])

  const getBigPhoto = (id) => {
    dispatch(openModal(id))
  }

  return (
    <div className="container">
      <Header>Test App</Header>
      <div className="list__content">
        {isFetching 
          ? <p>Loading...</p>
          : error 
          ? <p>{error}</p>
          : photos.map(({ id, url }) => (
              <List
                key={id}
                src={url}
                onClick={() => getBigPhoto(id)}
              />
            ))
        }
      </div>
      <Footer>&copy; 2019-2020</Footer>
      {isOpen && <ModalContainer />}
    </div>
  )
} 

export default App

在这一行中,我仅刷新一次照片,以刷新页面即可停止重新渲染

  useEffect(() => {
    dispatch(getPhotos())
  }, [])

当我单击照片时,我的模态打开,并且我想停止重新渲染所有组件。例如对于我的标头,我像这样使用React.memo HOC

import React, { memo } from 'react'
import './Header.scss'
import PropTypes from 'prop-types'

const Header = memo(({ children }) => {
  return <div className="header">{children}</div>
})

Header.propTypes = {
  children: PropTypes.string,
}

Header.defaultProps = {
  children: '',
}

export default Header

当我打开和关闭模态时,它可以完美地工作。页眉和页脚不重新呈现。但是,每次我打开和关闭模式窗口时,都会重新渲染List组件。之所以发生这种情况,是因为每次单击时,List组件中的道具onClick={() => getBigPhoto(id)}都会创建一个新的匿名函数。如您所知,如果道具改变了,组件将重新渲染。

我的问题是如何在我的情况下避免重新提交List组件?

1 个答案:

答案 0 :(得分:1)

您可以为List创建一个接收getBigPhoto和ID的容器,并使用useCallback创建getBigPhoto,以使函数不变:

const ListContainer = React.memo(function ListContainer({
  id,
  src,
  getBigPhoto,
}) {
  return (
    <List
      key={id}
      src={scr}
      onClick={() => getBigPhoto(id)}
    />
  );
});
const App = () => {
  const { isFetching, error, photos } = useSelector(
    ({ photos }) => photos
  );
  const { isOpen } = useSelector(({ modal }) => modal);
  const dispatch = useDispatch();

  useEffect(() => {
    dispatch(getPhotos());
  }, []);
  //use callback so getBigPhoto doesn't change
  const getBigPhoto = React.useCallback((id) => {
    dispatch(openModal(id));
  }, []);

  return (
    <div className="container">
      <Header>Test App</Header>
      <div className="list__content">
        {isFetching ? (
          <p>Loading...</p>
        ) : error ? (
          <p>{error}</p>
        ) : (
          photos.map(({ id, url }) => (
            // render pure component ListContainer
            <ListContainer
              key={id}
              src={url}
              id={id}
              getBigPhoto={getBigPhoto}
            />
          ))
        )}
      </div>
      <Footer>&copy; 2019-2020</Footer>
      {isOpen && <ModalContainer />}
    </div>
  );
};
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