我正在尝试为侧面项目制作无与伦比的井字游戏,但我做得不好(实际上我可以讽刺地打败它)。 它实际上是MiniMax算法的实现;我附带了这段代码
#include <iostream>
#include <string>
using namespace std;
struct Move
{
int line, columns;
};
//Return the number of remainings turn based on the number of lest boxes
int remainingsTurns(char grid[3][3])
{
int remainingTurn = 0;
for (int k = 0; k < 3; k++)
{
for (int i = 0; i < 3; i++)
{
if (grid[k][i] == ' ')
{
remainingTurn++;
}
}
}
return remainingTurn;
}
//Print the grid on screen
void printGrid(char grid[3][3])
{
for (int k = 0; k < 3; k++)
{
for (int i = 0; i < 3; i++)
{
cout << "| " << grid[k][i] << " ";
}
cout << "|" << endl;
}
}
//Give a value to the board
int evaluateBoard(char grid[3][3])
{
//Check the board for lines
for (int k = 0; k < 3; k++)
{
if (grid[k][0] == grid[k][1] && grid[k][1] == grid[k][2])
{
if (grid[k][0] == 'x')
{
return +10;
}
else if (grid[k][0] == 'o')
{
return -10;
}
}
}
//Check the board for columns
for (int k = 0; k < 3; k++)
{
if (grid[0][k] == grid[1][k] && grid[1][k] == grid[2][k])
{
if (grid[0][k] == 'x')
{
return +10;
}
else if (grid[0][k] == 'o')
{
return -10;
}
}
}
//Check the board for diagonals
if (grid[0][0] == grid[1][1] && grid[0][0] == grid[2][2])
{
if (grid[0][0] == 'x')
{
return +10;
}
else if (grid[0][0] == 'o')
{
return -10;
}
}
if (grid[0][2] == grid[1][1] && grid[0][2] == grid[2][0])
{
if (grid[0][0] == 'x')
{
return +10;
}
else if (grid[0][0] == 'o')
{
return -10;
}
}
//if no ictory return 0
return 0;
}
// MiniMax algorithm
int miniMax(char grid[3][3], int turn, bool maxMove)
{
int score = evaluateBoard(grid);
if (score == 10)
{
return score;
}
if (score == -10)
{
return score;
}
//Check if the game is a tie
if (remainingsTurns(grid) == 0)
{
return 0;
}
if (maxMove)
{
int best = -1000;
for (int k = 0; k < 3; k++)
{
for (int i = 0; i < 3; i++)
{
if (grid[k][i] == ' ')
{
grid[k][i] = 'x';
best = max(best, miniMax(grid, turn + 1, !maxMove));
grid[k][i] = ' ';
}
}
}
return best;
}
else
{
int best = 1000;
for (int k = 0; k < 3; k++)
{
for (int i = 0; i < 3; i++)
{
if (grid[k][i] == ' ')
{
grid[k][i] = 'o';
best = min(best, miniMax(grid, turn + 1, !maxMove));
grid[k][i] = ' ';
}
}
}
return best;
}
}
Move playerMov(char grid[3][3])
{
Move playerMove;
int input = -1;
cout << "Enter the column you want to play (1, 2 or 3)" << endl;
cin >> input;
if (input == 1 || input == 2 || input == 3)
{
playerMove.columns = input-1;
input = -1;
}
else
{
cout << "Error, enter a valid number!" << endl;
playerMov(grid);
}
cout << "Enter the line you want to play (1, 2 or 3)" << endl;
cin >> input;
if (input == 1 || input == 2 || input == 3)
{
playerMove.line = input-1;
input = -1;
}
else
{
cout << "Error, enter a valid number!" << endl;
playerMov(grid);
}
return playerMove;
}
//return the best move using the MiniMax
Move findMove(char grid[3][3])
{
int best = -1000;
Move move;
move.line = -1;
move.columns = -1;
//Check all move to find if this move is the best possible move
for (int k = 0; k < 3; k++)
{
for (int i = 0; i < 3; i++)
{
if (grid[k][i] == ' ')
{
grid[k][i] = 'x';
int moveValue = miniMax(grid, 0, false);
grid[k][i] = ' ';
if (moveValue > best)
{
move.line = k;
move.columns = i;
}
}
}
}
return move;
}
int main()
{
char grid[3][3];
int turn = 0;
Move playerMove, algoMove;
for (int k = 0; k < 3; k++)
{
for (int i = 0; i < 3; i++)
{
grid[k][i] = ' ';
}
}
cout << "Welcome to the unbeatable Tic Tac Toe !" << endl;
do
{
printGrid(grid);
playerMove = playerMov(grid);
grid[playerMove.line][playerMove.columns] = 'o';
Move computerMove = findMove(grid);
grid[computerMove.line][computerMove.columns] = 'x';
} while (remainingsTurns(grid) > 0);
cout << endl;
}
但是算法的运动似乎不正确,它总是选择右下角,我不明白为什么... 此实现很大程度上受到Geek for Geek的this文章的启发,在该文章中我尝试窃取该算法,但我无法使其正确以使其适合单个玩家。 我想念什么?
答案 0 :(得分:2)
您的代码中存在多个错误:
/article/123-my-title
函数grid[0][0]
中grid[0][2] == grid[1][1] && grid[0][2] == grid[2][0]
的值。应该是evaluateBoard
。grid[0][2]
中的playerMov(grid);
应该为playerMov
。否则,将丢弃重新输入的“正确”值,并返回(部分)未初始化的return playerMov(grid);
。playerMov
中将best
更新为moveValue
到moveValue > best
。 (这应该是引起您问题的原因)