Question

$jsonfile = file_get_contents("http://api.geonames.org/searchJSON?username=ksuhiyp&country=pt&maxRows=1000&style=SHORT");
    $jsondata = json_encode($jsonfile);
    $cities = explode(',', $jsondata);
    foreach($cities as $key => $value){
        echo $value;
    }

我如何只获取数组中包含的所有城市名称（例如，里斯本，波尔图，阿威罗...）？

以下是数组的示例：

{"totalResultsCount":37305,"geonames":[{"lng":"-9.13333","geonameId":2267057,"countryCode":"PT","name":"Lisbon","toponymName":"Lisbon","lat":"38.71667","fcl":"P","fcode":"PPLC"},{"lng":"-8.61099","geonameId":2735943,"countryCode":"PT","name":"Porto","toponymName":"Porto","lat":"41.14961","fcl":"P","fcode":"PPLA"},{"lng":"-8.42005","geonameId":2742032,"countryCode":"PT","name":"Braga","toponymName":"Braga","lat":"41.55032","fcl":"P","fcode":"PPLA"},{"lng":"-8.8882","geonameId":2262963,"countryCode":"PT","name":"Setúbal","toponymName":"Setúbal","lat":"38.5244","fcl":"P","fcode":"PPLA"},{"lng":"-8.13057","geonameId":2264397,"countryCode":"PT","name":"Portugal","toponymName":"Portuguese Republic","lat":"39.6945","fcl":"A","fcode":"PCLI"},

Answer 1

对于初学者来说，这是获取数据的一种非常丑陋的方式，因为您正在编码已经是json的json数据，然后仅循环遍历产生的整齐的字符串。

这将为您提供一个仅包含名称的数组：

$jsonfile = file_get_contents("http://api.geonames.org/searchJSON?username=ksuhiyp&country=pt&maxRows=1000&style=SHORT");
$geodat = json_decode($jsonfile,true);
$names = array();
foreach($geodat['geonames'] as $geoname) {
    $names[] = $geoname['name'];
}
print_r($names);

示例输出：

Array (
    [0] => Lisbon
    [1] => Porto
    [2] => Braga
    [3] => Setúbal
    [4] => Portugal
    [5] => Coimbra
    [6] => Funchal
    [7] => Amadora
    [8] => Queluz
    [9] => Lisbon metropolitan area
    ...

地理名称api循环并获取城市名称

1 个答案: