获取地理位置的城市名称

时间:2015-03-03 07:23:32

标签: javascript jquery geolocation

我在ASP.NET中使用HTML Geolocation来获取用户的位置。但是我需要获取CITY Name(例如:Paris,Kuala Lampur等),而不是传统上从以下代码输出的Latitude和Logitude:

<!DOCTYPE html>
<html>
<body>

<p id="demo">Click the button to get your position.</p>

<button onclick="getLocation()">Try It</button>

<div id="mapholder"></div>

<script src="http://maps.google.com/maps/api/js?sensor=false"></script>

<script>
var x = document.getElementById("demo");
function getLocation() {
    if (navigator.geolocation) {
        navigator.geolocation.getCurrentPosition(showPosition, showError);
    } else { 
        x.innerHTML = "Geolocation is not supported by this browser.";
    }
}

function showPosition(position) {
    lat = position.coords.latitude;
    lon = position.coords.longitude;
    latlon = new google.maps.LatLng(lat, lon)
    mapholder = document.getElementById('mapholder')
    mapholder.style.height = '250px';
    mapholder.style.width = '500px';

    var myOptions = {
    center:latlon,zoom:14,
    mapTypeId:google.maps.MapTypeId.ROADMAP,
    mapTypeControl:false,
    navigationControlOptions:{style:google.maps.NavigationControlStyle.SMALL}
    }

    var map = new google.maps.Map(document.getElementById("mapholder"), myOptions);
    var marker = new google.maps.Marker({position:latlon,map:map,title:"You are here!"});
}

function showError(error) {
    switch(error.code) {
        case error.PERMISSION_DENIED:
            x.innerHTML = "User denied the request for Geolocation."
            break;
        case error.POSITION_UNAVAILABLE:
            x.innerHTML = "Location information is unavailable."
            break;
        case error.TIMEOUT:
            x.innerHTML = "The request to get user location timed out."
            break;
        case error.UNKNOWN_ERROR:
            x.innerHTML = "An unknown error occurred."
            break;
    }
}
</script>

</body>
</html>

我试图在Page_Load的ASP页面上的标签上显示位置:)

2 个答案:

答案 0 :(得分:0)

这是一个反向地理编码问题。您可以使用任何反向地理编码服务,例如https://developers.google.com/maps/documentation/javascript/examples/geocoding-reverse

答案 1 :(得分:0)

这可以满足您的需求吗?

<!DOCTYPE html>
<html>
<head>
  <style>
    #mapholder {
      height: 300px;
      width: 300px;
    }
  </style>
</head>
<body>
<p id="demo">Click the button to get your position.</p>
<button onclick="getLocation()">Try It</button>
<div id="mapholder"></div>
<script src="http://maps.google.com/maps/api/js?sensor=true"></script>
<script>
var geocoder;  // this object will handle the position<->address conversion
var x = document.getElementById("demo");

function getLocation() {
    if (navigator.geolocation) {
        navigator.geolocation.getCurrentPosition(showPosition, showError); // , {maximumAge:60000, timeout:5000, enableHighAccuracy:true}
    } else { 
        x.innerHTML = "Geolocation is not supported by this browser.";
    }
}

function showPosition(position) {
    lat = position.coords.latitude;
    lon = position.coords.longitude;
    latlon = new google.maps.LatLng(lat, lon);
    // okay, now we have the position (as a google maps latLng object), 
    // now we send this position to geocoder
    // @see  https://developers.google.com/maps/documentation/javascript/geocoding
    geocoder = new google.maps.Geocoder();
    geocoder.geocode({'latLng': latlon}, function(results, status) {
      if (status == google.maps.GeocoderStatus.OK) {
        var city = getCity(results[0]);
        x.innerHTML = 'city: ' + city;
      }
    });

    mapholder = document.getElementById('mapholder');
    mapholder.style.height = '250px';
    mapholder.style.width = '500px';

    var myOptions = {
      center:latlon,zoom:14,
      mapTypeId:google.maps.MapTypeId.ROADMAP,
      mapTypeControl:false,
      navigationControlOptions:{style:google.maps.NavigationControlStyle.SMALL}
    }
    var map = new google.maps.Map(document.getElementById("mapholder"), myOptions);
    var marker = new google.maps.Marker({
      position:latlon,
      map:map,
      title:"You are here!"
    });
}

function showError(error) {
    switch(error.code) {
        case error.PERMISSION_DENIED:
            x.innerHTML = "User denied the request for Geolocation."
            break;
        case error.POSITION_UNAVAILABLE:

            x.innerHTML = "Location information is unavailable."
            break;
        case error.TIMEOUT:
            x.innerHTML = "The request to get user location timed out."
            break;
        case error.UNKNOWN_ERROR:
            x.innerHTML = "An unknown error occurred."
            break;
    }
}
// more info, see my post on http://stackoverflow.com/questions/27203977/google-api-address-components
function getCity(geocodeResponse) {
  var type = "locality";  //the function will look through the results and find a component with type = 'locatily'.  Then it returns that
  for(var i=0; i < geocodeResponse.address_components.length; i++) {
    for (var j=0; j < geocodeResponse.address_components[i].types.length; j++) {
      if (geocodeResponse.address_components[i].types[j] == type) {
        return geocodeResponse.address_components[i].long_name;
      }
    }
  }
  return '';
}
</script>
</body>
</html>