Question

我正在尝试向Google安全浏览查找API发送请求。它要求用户提供他想要查找的URL。但是，我发送请求的方式存在一些问题，因为它一直在回复错误代码400.请帮助。

import urllib
import urllib2
from google.appengine.ext import webapp
from google.appengine.ext.webapp import util
from google.appengine.api import urlfetch

req_url = "https://sb-ssl.google.com/safebrowsing/api/lookup"

class MainHandler(webapp.RequestHandler):
    def get(self):
        self.response.out.write("""<html>
                                    <body>
                                     <form action='' method='POST'>
                                      <input type='text' name='url'>
                                      <input type='submit' value='submit!!'>
                                     </form>
                                    </body>
                                   </html>""")
    def post(self):
        post_data = {'client':'api',
                     'apikey':'My-API-Key',
                     'appver':'1.5.2',
                     'pver':'3.0',
                     'url':"%s"% self.request.get('url') }
        data = urllib.urlencode(post_data)
        try:
            req = urlfetch.fetch(url = req_url,
                             payload = data,
                             method = urlfetch.POST,
                             headers = {'Content-Type': 'application/x-www-form-urlencoded'})
            if req.status_code == '200':
                self.response.out.write("success")
                self.response.out.write(req.content)
            else:
                self.response.out.write("Error code %s!!!"% req.status_code)
        except urllib2.URLError, e:
            self.response.out.write("Exception Raised")
            handleError(e)


def main():
  application = webapp.WSGIApplication([
                                        ('/', MainHandler)
                                        ],debug=True)

  util.run_wsgi_app(application)

if __name__ == '__main__':
  main()

Answer 1

您似乎没有遵循GET或POST方法的协议，但是通过POST传递应该是GET参数的内容正在做一些事情。

试试这个方法：

import urllib
from google.appengine.api import urlfetch

def safe_browsing(url):
    """Returns True if url is safe or False is it is suspect"""
    params = urllib.urlencode({
        'client':'api',
        'apikey':'yourkey',
        'appver':'1.5.2',
        'pver':'3.0',
        'url': url })
    url = "https://sb-ssl.google.com/safebrowsing/api/lookup?%s" % params
    res = urlfetch.fetch(url, method=urlfetch.GET)
    if res.status_code >= 400:
        raise Exception("Status: %s" % res.status_code)
    return res.status_code == 204

哪个会像：

>>> safe_browsing('http://www.yahoo.com/')
True

Google Safe-Browsing Lookup API中的无效请求

1 个答案: