Google安全浏览API对我不起作用

Question

我开始使用Google Console API，我想尝试使用Google安全浏览来检查网站是否包含恶意软件，或者该软件对我不起作用，这是我的代码：

public function check(){
    $url = 'http://www.facebokk.com';


    $apiKey = 'AI6k8kgflsgjhajjfldsjqldskqO2Iq5Ou0PE';
    $apiUrl = 'https://safebrowsing.googleapis.com/v4/threatMatches:find?key='.$apiKey;

    $params = [
          'client' => [
              'clientId' => 'foobar',
              'clientVersion' => '1.2.3'
          ],
          'threatInfo' => [
                 "threatTypes" =>["MALWARE", "SOCIAL_ENGINEERING"],
                "platformTypes" => ["WINDOWS"],
                 'threatEntryTypes' => ['URL'],
              'threatEntries' => [
                  [ 'url' => $url ]
              ]
          ]
      ];


    $ch = curl_init($apiUrl);
    curl_setopt_array($ch, [
                    CURLOPT_POST => 1,
                    CURLOPT_RETURNTRANSFER => 1,
                    CURLOPT_HEADER => 1,
                    CURLOPT_POSTFIELDS => json_encode($params),
                    CURLOPT_HTTPHEADER => [
                    'Content-Type: text/json'
                  ]
              ]);

    $res = curl_exec($ch);
    print_r($res, true);
}

这是结果：

  

HTTP / 1.1 200 OK内容类型：application / json; charset = UTF-8日期：2018年9月27日星期四15:13:54 GMT服务器：ESF缓存控制：专用X-XSS-保护：1; mode = block X-Frame-Options：SAMEORIGIN X-Content-Type-Options：nosniff Alt-Svc：quic =“：443”; ma = 2592000; v =“ 44,43,39,35”接受范围：无变化：接受编码传输编码：分块{}