代码花费超过1秒钟的时间
约束1≤T≤10^ 51≤P≤10^ 51≤H≤10^ 6
如何减少代码花费的时间
# cook your dish here
def check(h, p):
while p>0:
if h<=0:
return 1
if h-p>=0:
h = h-p
else:
h=0
p = p/2
# print(h,p)
return 0
for _ in range(int(input())):
h, p = map(int, input().split())
print(check(h,p))