Question

更改列表后，我得到了回应。我的回复看起来像这样：

{
 "response": [
    {
     "timestamp": "21:15-21:30",
     "logs": [
         {
             "exception": "IllegalAgrumentsException",
             "count": 1
         }
      ]
    },
    {
        "timestamp": "21:15-21:30",
        "logs": [
         {
             "exception": "NullPointerException",
             "count": 2
         }
     ]
   },..

我希望结果是这样的：-

 "response": [
     {
       "timestamp": "21:15-21:30",
       "logs": [
          {
              "exception": "IllegalAgrumentsException",
              "count": 1
          },
          {
              "exception": "NullPointerException",
              "count": 2
          } ]
   }

如何像上面在python中那样将日志合并在一起？

Answer 1

与other part of this question一样，这将是defaultdict时间……但我们需要在这里OrderedDict保持原始时间戳顺序。

import collections

input_data = [
    {
        "timestamp": "21:15-21:30",
        "logs": [{"exception": "IllegalAgrumentsException", "count": 1}],
    },
    {
        "timestamp": "21:15-21:30",
        "logs": [{"exception": "NullPointerException", "count": 2}],
    },
]

logs_by_timestamp = collections.OrderedDict()

for datum in input_data:
    logs_by_timestamp.setdefault(datum["timestamp"], []).extend(datum["logs"])

output_data = [
    {"timestamp": timestamp, "logs": logs}
    for (timestamp, logs) in logs_by_timestamp.items()
]

print(output_data)

输出（格式化）

[
    {
        "timestamp": "21:15-21:30",
        "logs": [
            {"exception": "IllegalAgrumentsException", "count": 1},
            {"exception": "NullPointerException", "count": 2},
        ],
    }
]

Answer 2

考虑您的情况。

查看以下补丁

_dict = {
    "response": [
        {
            "timestamp": "21:15-21:30",
            "logs": [
                {
                    "exception": "IllegalAgrumentsException",
                    "count": 1
                }
            ]
        },
        {
            "timestamp": "21:15-21:30",
            "logs": [
                {
                    "exception": "NullPointerException",
                    "count": 2
                }
            ]
        }]}

_final = {}
for _dict in _dict.get('response'):
    if not _dict.get('timestamp') in _final:
        _final[_dict.get('timestamp')] = {
            'timestamp': _dict.get('timestamp'),
            'logs': []
        }
    _final[_dict.get('timestamp')]['logs'] += _dict.get('logs')

_result ={'response': list(_final.values())}

print(_result)

将打印...

{
  'response': [
    {
      'timestamp': '21:15-21:30',
      'logs': [
        {
          'exception': 'IllegalAgrumentsException',
          'count': 1
        },
        {
          'exception': 'NullPointerException',
          'count': 2
        }
      ]
    }
  ]
}

Answer 3


response = [
    {
        "timestamp": "21:15-21:30",
        "logs": [{"exception": "IllegalAgrumentsException", "count": 1}],
    },
    {
        "timestamp": "21:15-21:30",
        "logs": [{"exception": "NullPointerException", "count": 2}],
    },
]

final = []
for k,v in groupby(response, lambda x:x.pop('timestamp')):
    final.append({
        'timestamp':k,
        'logs':reduce(
        lambda x,y:  {'logs':y['logs']+x['logs']},      
        [*v]
        )['logs']
    })
print(final)

Output 
[
    {
        "timestamp": "21:15-21:30",
        "logs": [
            {"exception": "IllegalAgrumentsException", "count": 1},
            {"exception": "NullPointerException", "count": 2},
        ],
    }
]

在python中将json从一种形式转换为另一种形式

3 个答案: