我正在尝试向所有僵尸程序发送消息,但我无法获得ID的整数。我得到元组,相反! 代码:
def send_msg_all_to(message):
try:
connect = pymysql.connect('localhost', 'root', '', 'python')
user_id = message.chat.id
text[user_id] = str(message.text)
if len(text[user_id]) < 2 or len(text[user_id]) >= 120:
raise ExpException("Error")
except ExpException as e:
msg = bot.send_message(message.chat.id, e)
bot.register_next_step_handler(msg, send_msg_all_to)
except ValueError as e:
msg = bot.send_message(message.chat.id, "Error")
bot.register_next_step_handler(msg, send_msg_all_to)
except pymysql.Error as e:
print("error in send_msg_all_to()", e)
else:
cursor = connect.cursor()
query = "SELECT usr_id FROM users"
cursor.execute(query)
users = cursor.fetchall()
msg = bot.send_message(message.chat.id, "Your message" % (text[user_id]))
bot.register_next_step_handler(msg, start)
for user in users:
print(user)
#bot.send_message(user, "Admin %s" % (text[user_id]))
finally:
connect.close()
此刻我在db中有2个ID,这是我的输出:
(1020347173,)
(130513514,)
我只想获取不带元组的所有ID(例如int),并将它们用于bot.send_message()
。你能帮我实现这个目标吗?
答案 0 :(得分:0)
由于仅选择一列,因此您将获得具有单个元素的元组。
因此,您只需要访问元组的第一个元素,即user[0]
:
for user in users:
print(user[0])
bot.send_message(user[0], "Admin %s" % (text[user_id]))