Question

我正在实习，我必须监视特定交换机的特定端口。如果端口连续多次断开连接，我决定发送电子邮件警报。为此，我已经在MySQL CLI中测试了此查询：

SELECT IF ((SELECT COUNT(message) FROM devices, ports, eventlog 
WHERE hostname = "HOSTNAME" 
AND message = "ifOperStatus: down -> up" 
AND ports.ifName = "0/8" and datetime >= now() - INTERVAL 45 MINUTE) >= 4, "ok", "false");

如果事件日志消息“ ifOperStatus：向下->向上”出现4次或+，则查询返回“确定”。

现在，我想编写一个连接到我的数据库的脚本，执行上一个查询，如果返回“ ok”，则发送电子邮件。我将设置一个cron作业以每分钟自动执行脚本。

问题是，我不知道该怎么做。我已经测试过了：

ScriptCode

#!/usr/bin/php
<?php
//connect to database
$dbconnect = mysql_connect('HOSTNAME', 'DB_Name', 'Passwd');
$result = $dbconnect->query(
  SELECT IF ((SELECT COUNT(message) FROM devices, ports, eventlog 
  WHERE hostname = "HOSTNAME" 
  AND message = "ifOperStatus: down -> up" 
  AND ports.ifName = "0/8" and datetime >= now() - INTERVAL 1 DAY) >= 4, "good", 
  "false"
);

//if there are any records matching this query we send an email listing each one using 'part_no' as the identifier in this case
if ($result = 'good') {
  $email = 'destination_mail';
  $subject = "Port alert";
  $message = "Port go down too much";
  if (mail($email, $subject, $message)) {
    // mail successfully sent
  } else {
    // mail unsuccessfull
  }
}

我真的很难写脚本。感谢您的帮助。

通过脚本发送警报邮件

0 个答案: