我使用10Gen认可的c#驱动程序用于mongoDB用于c#应用程序和数据浏览我正在使用Mongovue。
以下是两个示例文档架构:
{
"_id": {
"$oid": "4ded270ab29e220de8935c7b"
},
"Relationships": [
{
"RelationshipType": "Person",
"Attributes": {
"FirstName": "Travis",
"LastName": "Stafford"
}
},
{
"RelationshipType": "Student",
"Attributes": {
"GradMonth": "",
"GradYear": "",
"Institution": "Test1",
}
},
{
"RelationshipType": "Staff",
"Attributes": {
"Department": "LIS",
"OfficeNumber": "12",
"Institution": "Test2",
}
}
]
},
{
"_id": {
"$oid": "747ecc1dc1a79abf6f37fe8a"
},
"Relationships": [
{
"RelationshipType": "Person",
"Attributes": {
"FirstName": "John",
"LastName": "Doe"
}
},
{
"RelationshipType": "Staff",
"Attributes": {
"Department": "Dining",
"OfficeNumber": "1",
"Institution": "Test2",
}
}
]
}
我需要一个查询来确保满足$ elemMatch标准,以便我可以匹配第一个文档,但不能匹配第二个文档。以下查询适用于Mongovue。
{
'Relationships': { $all: [
{$elemMatch: {'RelationshipType':'Student', 'Attributes.Institution': 'Test1'}},
{$elemMatch: {'RelationshipType':'Staff', 'Attributes.Institution': 'Test2'}}
]}
}
如何在我的c#代码中执行相同的查询?
答案 0 :(得分:6)
使用c#驱动程序无法构建上述查询(至少在1.0版本中)。
但是你可以构建另一个更清晰的查询,它将返回相同的结果:
{ "Relationships" :
{ "$elemMatch" :
{ "RelationshipType" : "Test",
"Attributes.Institution" : { "$all" : ["Location1", "Location2"] }
}
}
}
来自c#的相同查询:
Query.ElemMatch("Relationships",
Query.And(
Query.EQ("RelationshipType", "Test"),
Query.All("Attributes.Institution", "Location1", "Location2")));
答案 1 :(得分:2)
一个简单的解决方案是将多个IMongoQuery串在一起,然后将它们与Query.And结合起来:
List<IMongoQuery> build = new List<IMongoQuery>();
build.Add(Query.ElemMatch("Relationships", Query.EQ("RelationshipType", "Person")));
var searchQuery = String.Format("/.*{0}.*/", "sta");
build.Add(Query.ElemMatch("Relationships", Query.Or(Query.EQ("Attributes.FirstName", new BsonRegularExpression(searchQuery)), Query.EQ("Attributes.LastName", new BsonRegularExpression(searchQuery)))));
var _main = Query.And(build.ToArray());
var DB = MongoDatabase.Create("UrlToMongoDB");
DB.GetCollection<ObjectToQuery>("nameOfCollectionInMongoDB").FindAs<ObjectToQuery>(_main).ToList();
`
答案 2 :(得分:1)
我通过构造一组允许生成以下查询的类来解决当前问题:
{ 'Relationships':
{
$all: [
{$elemMatch: {'RelationshipType':'Student', 'Attributes.Institution': 'Test1'}},
{$elemMatch: {'RelationshipType':'Staff', 'Attributes.Institution': 'Test2'}}
]
}
}
以下是类定义:
class MongoQueryAll
{
public string Name { get; set; }
public List<MongoQueryElement> QueryElements { get; set; }
public MongoQueryAll(string name)
{
Name = name;
QueryElements = new List<MongoQueryElement>();
}
public override string ToString()
{
string qelems = "";
foreach (var qe in QueryElements)
qelems = qelems + qe + ",";
string query = String.Format(@"{{ ""{0}"" : {{ $all : [ {1} ] }} }}", this.Name, qelems);
return query;
}
}
class MongoQueryElement
{
public List<MongoQueryPredicate> QueryPredicates { get; set; }
public MongoQueryElement()
{
QueryPredicates = new List<MongoQueryPredicate>();
}
public override string ToString()
{
string predicates = "";
foreach (var qp in QueryPredicates)
{
predicates = predicates + qp.ToString() + ",";
}
return String.Format(@"{{ ""$elemMatch"" : {{ {0} }} }}", predicates);
}
}
class MongoQueryPredicate
{
public string Name { get; set; }
public object Value { get; set; }
public MongoQueryPredicate(string name, object value)
{
Name = name;
Value = value;
}
public override string ToString()
{
if (this.Value is int)
return String.Format(@" ""{0}"" : {1} ", this.Name, this.Value);
return String.Format(@" ""{0}"" : ""{1}"" ", this.Name, this.Value);
}
}
帮助者搜索类:
public class IdentityAttributeSearch
{
public string Name { get; set; }
public object Datum { get; set; }
public string RelationshipType { get; set; }
}
示例用法:
public List<IIdentity> FindIdentities(List<IdentityAttributeSearch> searchAttributes)
{
var server = MongoServer.Create("mongodb://localhost/");
var db = server.GetDatabase("IdentityManager");
var collection = db.GetCollection<MongoIdentity>("Identities");
MongoQueryAll qAll = new MongoQueryAll("Relationships");
foreach (var search in searchAttributes)
{
MongoQueryElement qE = new MongoQueryElement();
qE.QueryPredicates.Add(new MongoQueryPredicate("RelationshipType", search.RelationshipType));
qE.QueryPredicates.Add(new MongoQueryPredicate("Attributes." + search.Name, search.Datum));
qAll.QueryElements.Add(qE);
}
BsonDocument doc = MongoDB.Bson.Serialization
.BsonSerializer.Deserialize<BsonDocument>(qAll.ToString());
var identities = collection.Find(new QueryComplete(doc)).ToList();
return identities;
}
我确信有一种更好的方法,但现在这种方法很有效,并且似乎足够灵活,可以满足我的需求。欢迎提出所有建议。
这可能是一个单独的问题,但出于某种原因,对于100,000个文档集,此搜索最多可能需要24秒。我试过添加各种索引但无济于事;在这方面的任何指针都很棒。