熊猫的Python直方图

Question

我正在尝试根据此数据集创建直方图：

我想要一个这样的图：

我写了这段代码：

import pandas as pd
import matplotlib.pyplot as plt
data = pd.read_csv('Data_Istogramma.csv', sep=';')
plt.hist(x =(data.iloc[0,1:6],data.iloc[1,1:6]),bins = 5,edgecolor = 'black',label =['80%','76.8%'])
plt.show()

一旦运行，我会得到这张图：

有人可以帮我吗？

Answer 1

您可以使用ploty来实现。您可以通过pip install plotly

安装

#sample df
import pandas as pd
df=pd.DataFrame({
    'lp':[70,85],
    '>850':[34,39],
    '700-850':[38,39],
    '425-700':[13,34],
    '250-425':[16,2],
    '<250':[25,10]
    
})

#reshape the df
df=df.melt(id_vars=['lp'])  
 
#use plotly library
import plotly.graph_objects as go

fig = go.Figure(data=[
    go.Bar(name='70', x=df[df['lp']==70]['variable'], y=df[df['lp']==70]['value']),
    go.Bar(name='85', x=df[df['lp']==85]['variable'], y=df[df['lp']==85]['value']),
])
# Change the bar mode
fig.update_layout(barmode='group')
fig.show()

Answer 2

使用字典定义行，并将标题行作为索引：

import pandas as pd
import matplotlib.pyplot as plt

eighty = [47.83, 5.24, 18.74, 22.22, 34.92, 137.75]
seventy_six = [61.47, 6.18, 54.37, 3.22, 16.52, 156.38]
LP = [">850",
      "850-700",
      "700-425",
      "425-250",
      "<250",
      "MTOT"
      ]

df = pd.DataFrame({'80': eighty,
                   '76.8': seventy_six},
                  index=LP)

ax = df.plot.bar(rot=0)
plt.show()

返回：