科特林会议室加入三桌

Question

我从三个表中都有一个对象，我尝试这样做：

@Parcelize
@Entity(tableName = "table_one")
data class OneItem(
    @PrimaryKey
    @ColumnInfo(name = "id")
    val id: Long,
    val name: String? = null,
   
):Parcelable

@Parcelize
@Entity(tableName = "table_two")
data class TableTwo(
    @PrimaryKey
    @ColumnInfo(name = "label")
    val label: Long,
    val value: String? = null

):Parcelable

@Parcelize
@Entity(tableName = "table_three", primaryKeys = ["id_table_one", "type"])
data class Three(
    @ColumnInfo(name = "id_table_one") val id_table_one: Long,
    @ColumnInfo(name = "type") val type: Int,
    @ColumnInfo(name = "card_id") var cardId: String? = null,
):Parcelable

我尝试从表1中获取一行对象，从表2中获取对象，并从表3中获取对象，我尝试这样做：

    class BigClass(
        @Embedded val oneItem: OneItem,
        @Embedded val tableTwo: TableTwo,
        @Relation(
            parentColumn = "id",
            entityColumn = "id_table_one",
            entity = Three::class
        )
        val three: List<Three>
    )

当我尝试构建应用程序时出现错误；

Eror：用@Relation注释的字段不能是构造函数参数。这些值是在构造对象之后获取的