Question

使用flutter blue plugin（0.5.0版）时遇到问题。

我的Bluetooth设备仅连接一次，直到关闭iPhone上的Bluetooth并再次打开它之后，我才能再次连接。

这是实验的视频。 https://drive.google.com/file/d/1pQW4JFQI5R_zcxF3wfozT6Ru2AY2KxBm/view?usp=sharing

我无法使用最新的插件版本，因为该项目很旧。此问题仅在ios中发生。

这是我的连接代码：

_connect(BluetoothDevice d) async {
device = d;
// Connect to device
deviceConnection = _flutterBlue
    .connect(device, timeout: const Duration(seconds: 4))
    .listen(
  null,
  onDone: _disconnect,
);

// Update the connection state immediately
device.state.then((s) {
  setState(() {
    deviceState = s;
  });
});

// Subscribe to connection changes
deviceStateSubscription = device.onStateChanged().listen((s) {
  if (mounted)
    setState(() {
      deviceState = s;
    });
  if (s == BluetoothDeviceState.connected) {
    device.discoverServices().then((s) {
      var bservice = s
          .where((r) =>
          r.uuid
              .toString()
              .toLowerCase()
              .contains("0000ffe0-0000-1000-8000-00805f9b34fb"))
          .first;
      if (bservice != null) {
        var char = bservice.characteristics
            .where((c) =>
            c.uuid
                .toString()
                .toLowerCase()
                .contains("0000ffe4-0000-1000-8000-00805f9b34fb"))
            .first;
        if (char != null) {
          _setNotification(char);
        }
      }
      bservice = s
          .where((r) =>
          r.uuid
              .toString()
              .toLowerCase()
              .contains("00001808-0000-1000-8000-00805f9b34fb"))
          .first;
      if (bservice != null) {
        var char = bservice.characteristics
            .where((c) =>
            c.uuid
                .toString()
                .toLowerCase()
                .contains("00002a18-0000-1000-8000-00805f9b34fb"))
            .first;
        if (char != null) {
          _setNotification(char);
        }
      }

      setState(() {
        //Accu-Answer isaw Service UUID="0000ffe0-0000-1000-8000-00805f9b34fb"
        //Accu-Answer isaw Characteristics UUID="0000ffe4-0000-1000-8000-00805f9b34fb"
        //YASEE Service UUID="00001808-0000-1000-8000-00805f9b34fb"
        //YASEE Characteristics UUID="00002a18-0000-1000-8000-00805f9b34fb"

        // var bservice=s.where((r) =>r.uuid.toString().toLowerCase().contains("0000ffe0-0000-1000-8000-00805f9b34fb")).first;//Accu-Answer
        // var bservice=s.where((r) =>r.uuid.toString().toLowerCase().contains("00001808-0000-1000-8000-00805f9b34fb")).first;//YASEE
        for (int i = 0; i < s.length; i++) {
          var bservice = s[i];
          var tmpUUID = bservice.uuid.toString().toLowerCase();

          if (tmpUUID == "0000ffe0-0000-1000-8000-00805f9b34fb") {
            var char = bservice.characteristics
                .where((c) =>
                c.uuid
                    .toString()
                    .toLowerCase()
                    .contains("0000ffe4-0000-1000-8000-00805f9b34fb"))
                .first;
            if (char != null) {
              _setNotification(char);
            }
            break;
          } else if (tmpUUID == "00001808-0000-1000-8000-00805f9b34fb") {
            var char = bservice.characteristics
                .where((c) =>
                c.uuid
                    .toString()
                    .toLowerCase()
                    .contains("00002a18-0000-1000-8000-00805f9b34fb"))
                .first;
            if (char != null) {
              _setNotification(char);
            }
            break;
          }
        }

        //services = s;
      });
    });
  }
});}

我正在iPhone 6和ios版本12.4.7上进行测试

Answer 1

我对Flutter blue lib有很多问题，因此决定尝试另一个库，但我的问题消失了。传输代码应该没有问题。该API有所不同，但示例很好而扎实。

这是我使用的软件包，我强烈推荐它：https://pub.dev/packages/flutter_ble_lib

在iOS上扑动蓝牙问题

1 个答案: