您好,我是tkinter和python的新手,所以我想知道是否有什么办法可以让我使用“添加”按钮在“历史记录”下方打印“名称”,“电子邮件”和“密码”条目标签。目的是帮助您记住您的帐户。虽然我不需要关闭时保留此数据的功能。 任何帮助将非常感激, 谢谢。 这是我的代码:
from tkinter import *
import tkinter as tk
root = Tk()
root.title("Login")
username = "Sam"
password = "Sam"
#username entry
username_entry = Entry(root, borderwidth=10)
#password entry
password_entry = Entry(root, show='*', borderwidth=10)
username_entry.grid(row=1,column=2)
password_entry.grid(row=2,column=2)
myLabel1 = Label(root,text="Username")
myLabel2 = Label(root,text="Password")
myLabel1.grid(row=1, column=0)
myLabel2.grid(row=2, column=0)
def trylogin():
if username == username_entry.get() and password == password_entry.get():
print("Correct")
createNewWindow()
else:
print("Wrong")
def createNewWindow():
newWindow = tk.Toplevel(root)
newWindow.title("Accounts")
#ENTRY'S
e1 = Entry(newWindow, width=50)
e2 = Entry(newWindow, width=50)
e3 = Entry(newWindow, width=50)
e1.grid(row=1, column=2)
e2.grid(row=2, column=2)
e3.grid(row=3, column=2)
#LABELS
myLabel1 = Label(newWindow, text="Name")
myLabel2 = Label(newWindow, text="EMAIL:")
myLabel3 = Label(newWindow, text="PASSWORD:")
myLabel4 = Label(newWindow, text="History:")
myLabel1.grid(row=1, column=0)
myLabel2.grid(row=2, column=0)
myLabel3.grid(row=3, column=0)
myLabel4.grid(row=4, column=1)
def addToWindow():
myLabel5 = Label(newWindow, text="Name: " + e1.get())
myLabel6 = Label(newWindow, text="Email: " + e2.get())
myLabel7 = Label(newWindow, text="Password: " + e3.get())
myLabel5.grid(row=7, column=1)
myLabel6.grid(row=8, column=1)
myLabel7.grid(row=9, column=1)
button = Button(newWindow, text="Add", command = addToWindow)
button.grid(row=4, column=2)
button = Button(root, text="check", command = trylogin)
button.grid(row=3, column=2)
root.mainloop()
app.mainloop()
答案 0 :(得分:0)
我在createNewWindow函数中添加了一个函数,以将输入字段的值写入历史记录标题下方。这可能更漂亮,但是您列出了值。
下面的代码。将其放在脚本的第53行,然后在Button函数中为添加按钮调用命令。
from tkinter import *
import tkinter as tk
root = Tk()
root.title("Login")
username = "username"
password = "password"
#username entry
username_entry = Entry(root, borderwidth=10)
#password entry
password_entry = Entry(root, show='*', borderwidth=10)
username_entry.grid(row=1,column=2)
password_entry.grid(row=2,column=2)
myLabel1 = Label(root,text="Username")
myLabel2 = Label(root,text="Password")
myLabel1.grid(row=1, column=0)
myLabel2.grid(row=2, column=0)
def trylogin():
if username == username_entry.get() and password == password_entry.get():
print("Correct")
createNewWindow()
else:
print("Wrong")
def createNewWindow():
newWindow = tk.Toplevel(root)
newWindow.title("Accounts")
#ENTRY'S
e1 = Entry(newWindow, width=50)
e2 = Entry(newWindow, width=50)
e3 = Entry(newWindow, width=50)
e1.grid(row=1, column=2)
e2.grid(row=2, column=2)
e3.grid(row=3, column=2)
#LABELS
myLabel1 = Label(newWindow, text="Name")
myLabel2 = Label(newWindow, text="EMAIL:")
myLabel3 = Label(newWindow, text="PASSWORD:")
myLabel4 = Label(newWindow, text="History:")
myLabel1.grid(row=1, column=0)
myLabel2.grid(row=2, column=0)
myLabel3.grid(row=3, column=0)
myLabel4.grid(row=5, column=1)
def addToWindow():
myLabel5 = Label(newWindow, text="Name: " + e1.get())
myLabel6 = Label(newWindow, text="Email: " + e2.get())
myLabel7 = Label(newWindow, text="Password: " + e3.get())
myLabel5.grid(row=7, column=1)
myLabel6.grid(row=8, column=1)
myLabel7.grid(row=9, column=1)
button = Button(newWindow, text="Add", command = addToWindow)
button.grid(row=4, column=2)
button = Button(root, text="check", command = trylogin)
button.grid(row=3, column=2)
root.mainloop()
#app.mainloop()
答案 1 :(得分:0)
针对您的要求的次要修复程序,将其移至Newwindow函数内
void f1_1(int)