Question

我有一个旅行对象，看起来像这样：

Array (1)
0 {id: 1, vehicle: {freeSeats: 2, __typename: "Vehicle"}, startLocation: "{\"type\":\"Point\",\"coordinates\":[8.217462,53.13975]}", endLocation: "{\"type\":\"Point\",\"coordinates\":[8.258844,53.119525]}", timeOfDeparture: "2020-06-16T11:48:00.869Z", …}

type TripListProps = {
  trips: any; //TODO FIX
  //trips: Array<Trip>,
  friendIds: Array<number>,
};

export const TripList: React.FunctionComponent<TripListProps> = ({ trips, friendIds }) => {
  console.log('trips', trips);
  if (trips.length > 0) {
    return ( 
      <View style={{ height: 500 }}>
        <FlatList
          data={trips}
          horizontal={false}
          scrollEnabled
          renderItem={({ item }) => <TripContainer trip={item} friendIds={friendIds} />}
          keyExtractor={(trip: any) => trip.id.toString()}
        />
      </View>
    )
  } else {
    return (<View style={styles.noTripsFound}>
    <Text style={styles.text}>No trips found</Text></View>);
  }
};

其原始类型为Array<Trip>。但是，在这里，我将其传递给另一个组件TripContainer，该组件需要使用以下形式的行程：

trip: {
  driver: {
      firstName: string;
      rating: number;
      id: number;
  };
  timeOfDeparture: any;
}

因此，如果我将TripListProps从trips: any更改为trips: Array<Trip>，则会收到错误消息。

有什么方法可以从整个数组对象中仅提取这部分吗？

Answer 1

您可以在lodash中使用_.pick来仅选择有钥匙的钥匙

var object = { 'a': 1, 'b': '2', 'c': 3 };

_.pick(object, ['a', 'c']);
// => { 'a': 1, 'c': 3 }

从数组中提取对象-打字稿

1 个答案: